HDU 1002 A + B Problem II

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 149365    Accepted Submission(s): 28157

Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
 

 

Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
 

 

Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
 

 

Sample Input
2
1 2
112233445566778899 998877665544332211
 

 

Sample Output
Case 1:
1 + 2 = 3
 
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
 

 

Author
Ignatius.L
 
 
 
 
import java.util.*;
import java.math.*;

public class Main{
    public static void main(String[] args){
        Scanner cin = new Scanner(System.in);
        int t;
        BigInteger a,b;
        t = cin.nextInt();
        int cases = 0;
        while(t != 0){
            t--;
            a = cin.nextBigInteger();
            b = cin.nextBigInteger();
            System.out.println("Case " + (++cases) +":");
            System.out.println(a + " + " + b + " = " + a.add(b));
            if(t != 0)
                System.out.println();
        }
    }
}

 

posted @ 2013-03-30 10:21  Jack Ge  阅读(310)  评论(0编辑  收藏  举报