Python项目目录树生成

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收起

1、生成项目目录树

在当前文件所在文件夹下运行。

2、代码

dir_tree.py

# -*- coding: utf-8 -*-
import sys
from pathlib import Path
 
 
class DirectionTree(object):
    """生成目录树
    @ pathname: 目标目录
    @ filename: 要保存成文件的名称
    """
 
    def __init__(self, pathname='.', filename='tree.txt'):
        super(DirectionTree, self).__init__()
        self.pathname = Path(pathname)
        self.filename = filename
        self.tree = ''
 
    def set_path(self, pathname):
        self.pathname = Path(pathname)
 
    def set_filename(self, filename):
        self.filename = filename
 
    def generate_tree(self, n=0):
        if self.pathname.is_file():
            self.tree += '    |' * n + '-' * 4 + self.pathname.name + '\n'
        elif self.pathname.is_dir():
            self.tree += '    |' * n + '-' * 4 + \
                str(self.pathname.relative_to(self.pathname.parent)) + '\\' + '\n'
 
            for cp in self.pathname.iterdir():
                self.pathname = Path(cp)
                self.generate_tree(n + 1)
 
    def save_file(self):
        with open('./'+self.filename, 'w', encoding='utf-8') as f:
            f.write(self.tree)
        print("已保存文件！")
 
 
if __name__ == '__main__':
    # 运行
    # python dir_tree.py D:\Work\SlabSerialRecognition\MyCRNN_Slab dir_tree.txt

    dirtree = DirectionTree()
    # 命令参数个数为1，生成当前目录的目录树
    if len(sys.argv) == 1:
        dirtree.set_path(Path.cwd())
        dirtree.generate_tree()
        dirtree.save_file()
        print(dirtree.tree)
    # 命令参数个数为2并且目录存在存在
    elif len(sys.argv) == 2 and Path(sys.argv[1]).exists():
        dirtree.set_path(sys.argv[1])
        dirtree.generate_tree()
        print(dirtree.tree)
    # 命令参数个数为3并且目录存在存在
    elif len(sys.argv) == 3 and Path(sys.argv[1]).exists():
        dirtree.set_path(sys.argv[1])
        dirtree.generate_tree()
        dirtree.set_filename(sys.argv[2])
        dirtree.save_file()
    else:  # 参数个数太多，无法解析
        print('命令行参数太多，请检查！')