PHP伪造referer访问地址

 1、方法一（CURL）：

$ch = curl_init();
curl_setopt ($ch, CURLOPT_URL, "https://www.jiansouti.com");
curl_setopt ($ch, CURLOPT_REFERER, "https://www.jiansouti.com");
curl_exec ($ch);
curl_close ($ch);

2、方法二（fsockopen）：

$server = 'www.jiansouti.com';
$host = 'www.jiansouti.com';
$target = 'api.php';
$referer = 'https://www.jiansouti.com/'; // Referer 
$port = 80;
$fp = fsockopen($server, $port, $errno, $errstr, 30);
if (!$fp){
    echo "$errstr ($errno)＼n";
}else{
    $out = "GET $target HTTP/1.1＼r＼n";
    $out .= "Host: $host＼r＼n";
    $out .= "Referer: $referer＼r＼n";
    $out .= "Connection: Close＼r＼n＼r＼n";
    fwrite($fp, $out);
    while (!feof($fp)){
        echo fgets($fp, 128);
    }
    fclose($fp);
}