mysql 返回自增id

        String dateNow=  DateTime.Now.ToString("yyyyMMddhhmmss"+  new Random().Next(1, 99)); //随机数


                    StringBuilder sqlStr = new StringBuilder();
                    //1.添加年卡基础信息,获得自增ID
                    sqlStr.Append(" insert  a set a.id=1;  select @@IDENTITY " ,
                       

                    //自增id
                     int num = int.Parse(Shove.Database.MySQL.ExecuteScalar(sqlStr.ToString()).ToString());

posted @ 2017-07-20 18:56  越过那个限制  阅读(426)  评论(0编辑  收藏  举报