leetcode-1331-easy

Rank Transform of an Array

Given an array of integers arr, replace each element with its rank.

The rank represents how large the element is. The rank has the following rules:

Rank is an integer starting from 1.
The larger the element, the larger the rank. If two elements are equal, their rank must be the same.
Rank should be as small as possible.
Example 1:

Input: arr = [40,10,20,30]
Output: [4,1,2,3]
Explanation: 40 is the largest element. 10 is the smallest. 20 is the second smallest. 30 is the third smallest.
Example 2:

Input: arr = [100,100,100]
Output: [1,1,1]
Explanation: Same elements share the same rank.
Example 3:

Input: arr = [37,12,28,9,100,56,80,5,12]
Output: [5,3,4,2,8,6,7,1,3]
Constraints:

0 <= arr.length <= 105
-109 <= arr[i] <= 109

思路一:数组排序后,用 map 存储对应的 rank,最后对所求数组用 map 进行替换

public int[] arrayRankTransform(int[] arr) {
    int[] copy = Arrays.copyOf(arr, arr.length);

    Arrays.sort(copy);

    Map<Integer, Integer> rankMap = new HashMap<>();
    int rank = 1;
    for (int j : copy) {
        if (!rankMap.containsKey(j)) {
            rankMap.put(j, rank);
            rank++;
        }
    }

    for (int i = 0; i < arr.length; i++) {
        arr[i] = rankMap.get(arr[i]);
    }

    return arr;
}
posted @   iyiluo  阅读(4)  评论(0编辑  收藏  举报
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