Max Sum
Problem Description
Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.
Sample Input
2
5 6 -1 5 4 -7
7 0 6 -1 1 -6 7 -5
Sample Output
Case 1:
14 1 4
Case 2:
7 1 6
AC代码:
1 import java.util.Scanner; 2 3 public class Main { 4 5 public static void main(String[] args) { 6 Scanner sc = new Scanner(System.in); 7 int n = sc.nextInt(); //输入测试次数 8 int temp = 1; 9 int startIndex = 1; //开始位置 10 int endIndex = 1; //结束位置 11 int sum = 0; //和 12 //设置max为最小负数 13 int max = -0xfffffff; 14 for (int i = 0; i < n; i++) { 15 int m = sc.nextInt(); //输入数的个数 16 for (int j = 0; j < m; j++) { 17 sum += sc.nextInt(); 18 if (sum > max) { //当输入的所有数之后就是最大值时 19 max = sum; 20 startIndex = temp; 21 endIndex = j + 1; 22 } 23 //这里不能用else if 因为当输入的数包含负数和零时,只会执行上面的if 24 if (sum < 0) { 25 sum = 0; 26 temp = j + 2; 27 } 28 } 29 System.out.println("Case " + (i + 1) + ":"); 30 System.out.println(max + " " + startIndex + " " + endIndex); 31 32 sum = 0; 33 max = -0xfffffff; 34 startIndex = 1; 35 endIndex = 1; 36 temp = 1; 37 if (i != n - 1) { 38 System.out.println(); 39 } 40 } 41 } 42 }