摘要: function getPositionTop(node) { var top = node.offsetTop; var parent = node.offsetParent; while(parent != null) { top += parent.offsetTop; parent = parent.offsetParent; } return top... 阅读全文
posted @ 2018-10-08 14:02 expworld 阅读(348) 评论(0) 推荐(0) 编辑