TapeEquilibrium - Codility Lesson3

def solution(A):

  # write your code in Python 3.6

  result = 100000

  P = 1

  while P < len(A):

    B=sum(A[0:P])

    C=sum(A[P:])

    result = min(result,abs(B-C))

    P +=1

  return result

  pass

posted @ 2020-08-05 15:52  挨特·李  阅读(75)  评论(0)    收藏  举报