挑战程序设计竞赛 习题 poj 3050 Hopscotch
地址 https://vjudge.net/problem/POJ-3050
The cows play the child's game of hopscotch in a non-traditional way.
Instead of a linear set of numbered boxes into which to hop, the cows create a 5x5 rectilinear grid of digits parallel to the x and y axes. They then adroitly hop onto any digit in the grid and hop forward, backward, right, or left (never diagonally) to another digit in the grid.
They hop again (same rules) to a digit (potentially a digit already visited). With a total of five intra-grid hops, their hops create a six-digit integer (which might have leading zeroes like 000201). Determine the count of the number of distinct integers that can be created in this manner. Input * Lines 1..5: The grid, five integers per line Output * Line 1: The number of distinct integers that can be constructed Sample Input 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 Sample Output 15 Hint OUTPUT DETAILS: 111111, 111112, 111121, 111211, 111212, 112111, 112121, 121111, 121112, 121211, 121212, 211111, 211121, 212111,
and 212121 can be constructed.
No other values are possible.
代码
#include <iostream> #include <set> #include <vector> using namespace std; int arr[6][6]; set<vector<int>> ss; int addx[4] = {1,-1,0,0}; int addy[4] = {0,0,-1,1}; void dfs(int x,int y,vector<int>& v) { if(v.size() == 6){ ss.insert(v); return; } v.push_back(arr[x][y]); for(int i =0;i < 4;i++){ int newx = x+ addx[i]; int newy = y +addy[i]; if(newx>=0 && newx<5 && newy>=0 && newy <5){ dfs(newx,newy,v); } } v.pop_back(); return ; } int main(){ for(int i =0; i < 5;i++){ for(int j = 0; j<5;j++){ cin >> arr[i][j]; } } for(int i =0; i < 5;i++){ for(int j = 0; j<5;j++){ vector<int> v; dfs(i,j,v); } } cout << ss.size() << endl; return 0; }
作 者: itdef
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欢迎转帖 请保持文本完整并注明出处
技术博客 http://www.cnblogs.com/itdef/
B站算法视频题解
https://space.bilibili.com/18508846
qq 151435887
gitee https://gitee.com/def/
欢迎c c++ 算法爱好者 windows驱动爱好者 服务器程序员沟通交流
如果觉得不错,欢迎点赞,你的鼓励就是我的动力