多线程-共享全局变量

from threading import Thread
import time

g_num = 100

def work1():
    global g_num
    for i in range(3):
        g_num += 1

    print("----in work1, g_num is %d---"%g_num)


def work2():
    global g_num
    print("----in work2, g_num is %d---"%g_num)


print("---线程创建之前g_num is %d---"%g_num)

t1 = Thread(target=work1)
t1.start()

#延时一会,保证t1线程中的事情做完
time.sleep(1)

t2 = Thread(target=work2)
t2.start()

运行结果:

---线程创建之前g_num is 100---
----in work1, g_num is 103---
----in work2, g_num is 103---

列表当做实参传递到线程中

from threading import Thread
import time

def work1(nums):
    nums.append(44)
    print("----in work1---",nums)


def work2(nums):
    #延时一会,保证t1线程中的事情做完
    time.sleep(1)
    print("----in work2---",nums)

g_nums = [11,22,33]

t1 = Thread(target=work1, args=(g_nums,))
t1.start()

t2 = Thread(target=work2, args=(g_nums,))
t2.start()

运行结果:

----in work1--- [11, 22, 33, 44]
----in work2--- [11, 22, 33, 44]


多线程-共享全局变量问题

多线程开发可能遇到的问题

假设两个线程t1和t2都要对全局变量g_num(默认是0)进行加1运算,t1和t2都各对g_num加10次,g_num的最终的结果应该为20。

但是由于是多线程同时操作,有可能出现下面情况:

  1. 在g_num=0时,t1取得g_num=0。此时系统把t1调度为”sleeping”状态,把t2转换为”running”状态,t2也获得g_num=0
  2. 然后t2对得到的值进行加1并赋给g_num,使得g_num=1
  3. 然后系统又把t2调度为”sleeping”,把t1转为”running”。线程t1又把它之前得到的0加1后赋值给g_num。
  4. 这样导致虽然t1和t2都对g_num加1,但结果仍然是g_num=1

测试1

import threading
import time

g_num = 0

def work1(num):
    global g_num
    for i in range(num):
        g_num += 1
    print("----in work1, g_num is %d---"%g_num)


def work2(num):
    global g_num
    for i in range(num):
        g_num += 1
    print("----in work2, g_num is %d---"%g_num)


print("---线程创建之前g_num is %d---"%g_num)

t1 = threading.Thread(target=work1, args=(100,))
t1.start()

t2 = threading.Thread(target=work2, args=(100,))
t2.start()

while len(threading.enumerate()) != 1:
    time.sleep(1)

print("2个线程对同一个全局变量操作之后的最终结果是:%s" % g_num)

运行结果:

---线程创建之前g_num is 0---
----in work1, g_num is 100---
----in work2, g_num is 200---
2个线程对同一个全局变量操作之后的最终结果是:200

测试2

import threading
import time

g_num = 0

def work1(num):
    global g_num
    for i in range(num):
        g_num += 1
    print("----in work1, g_num is %d---"%g_num)


def work2(num):
    global g_num
    for i in range(num):
        g_num += 1
    print("----in work2, g_num is %d---"%g_num)


print("---线程创建之前g_num is %d---"%g_num)

t1 = threading.Thread(target=work1, args=(1000000,))
t1.start()

t2 = threading.Thread(target=work2, args=(1000000,))
t2.start()

while len(threading.enumerate()) != 1:
    time.sleep(1)

print("2个线程对同一个全局变量操作之后的最终结果是:%s" % g_num)

运行结果:

---线程创建之前g_num is 0---
----in work1, g_num is 1088005---
----in work2, g_num is 1286202---
2个线程对同一个全局变量操作之后的最终结果是:1286202

结论

  • 如果多个线程同时对同一个全局变量操作,会出现资源竞争问题,从而数据结果会不正确

总结:

  • 在一个进程内的所有线程共享全局变量,很方便在多个线程间共享数据
  • 缺点就是,线程是对全局变量随意遂改可能造成多线程之间对全局变量的混乱(即线程非安全)
posted @ 2019-04-27 22:09  阿磊小哥哥呀  阅读(139)  评论(0编辑  收藏  举报