【UVA - 488 Triangle Wave】
Triangle Wave |
In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.
Input and Output
The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.
Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.
For each test case, the output must follow the descri_ption below. The outputs of two consecutive cases will be separated by a blank line.
For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.
The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.
NOTE: There is a blank line after each separate waveform, excluding the last one.
Sample Input
1 3 2
Sample Output
1 22 333 22 1 1 22 333 22 1
1 // Project name : H ( Triangle Wave ) 2 // File name : main.cpp 3 // Author : Izumu 4 // Date & Time : Tue Jul 10 20:32:18 2012 5 6 7 #include <iostream> 8 #include <stdio.h> 9 #include <string> 10 #include <cmath> 11 using namespace std; 12 13 int main() 14 { 15 int t; 16 cin >> t; 17 while (t--) 18 { 19 20 int n, m; 21 cin >> n >> m; 22 for (int k = 0; k < m; k++) 23 { 24 if (k) 25 { 26 cout << endl; 27 } 28 for (int i = 1; i <= n; i++) 29 { 30 for (int j = 0; j < i; j++) 31 { 32 cout << i; 33 } 34 cout << endl; 35 } 36 for (int i = n - 1; i >= 1; i--) 37 { 38 for (int j = 0; j < i; j++) 39 { 40 cout << i; 41 } 42 cout << endl; 43 } 44 45 } 46 47 if (t) 48 { 49 cout << endl; 50 } 51 } 52 return 0; 53 } 54 55 // end 56 // ism