【ECJTU_ACM 11级队员2012年暑假训练赛（8） - H - Petya and Strings】

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ECJTU_ACM 11级队员2012年暑假训练赛（8）
4:30:00
 
 
          
H - Petya and Strings
Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Description

Little Petya loves presents. His mum bought him two strings of the same size for his birthday. The strings consist of uppercase and lowercase Latin letters. Now Petya wants to compare those two strings lexicographically. The letters' case does not matter, that is an uppercase letter is considered equivalent to the corresponding lowercase letter. Help Petya perform the comparison.

Input

Each of the first two lines contains a bought string. The strings' lengths range from 1 to 100 inclusive. It is guaranteed that the strings are of the same length and also consist of uppercase and lowercase Latin letters.

Output

If the first string is less than the second one, print "-1". If the second string is less than the first one, print "1". If the strings are equal, print "0". Note that the letters' case is not taken into consideration when the strings are compared.

Sample Input

Input
aaaa
aaaA
Output
0
Input
abs
Abz
Output
-1
Input
abcdefg
AbCdEfF
Output
1

Hint

If you want more formal information about the lexicographical order (also known as the "dictionary order" or "alphabetical order"), you can visit the following site:

 

  • http://en.wikipedia.org/wiki/Lexicographical_order

 

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 1 // Project name : H ( Petya and Strings ) 
 2 // File name    : main.cpp
 3 // Author       : iCoding
 4 // E-mail       : honi.linux@gmail.com
 5 // Date & Time  : Fri Aug 10 13:14:48 2012
 6 
 7 
 8 #include <iostream>
 9 #include <stdio.h>
10 #include <string>
11 #include <cmath>
12 #include <algorithm>
13 using namespace std;
14 
15 /*************************************************************************************/
16 /* data */
17 string sa, sb;
18 
19 /*************************************************************************************/
20 /* procedure */
21 
22 int iCalForResult()
23 {
24     int iTop = sa.length() - 1;
25     for (int i = 0; i <= iTop; i++)
26     {
27         if (sa[i] >= 'A' && sa[i] <= 'Z')
28         {
29             sa[i] += 32;
30         }
31         if (sb[i] >= 'A' && sb[i] <= 'Z')
32         {
33             sb[i] += 32;
34         }
35     }
36 
37     int res = 0;
38     for (int i = 0; res == 0 && i <= iTop; i++)
39     {
40         if (sa[i] > sb[i])
41         {
42             res = 1;
43         }
44         else if (sa[i] < sb[i])
45         {
46             res = -1;
47         }
48     }
49     return res;
50 }
51 /*************************************************************************************/
52 /* main */
53 int main()
54 {
55     while (cin >> sa >>sb)
56     {
57         cout << iCalForResult() << endl;
58     }
59     return 0;
60 }
61 
62 // end 
63 // Code by Sublime text 2
64 // iCoding@CodeLab
posted @ 2012-08-13 10:55  ismdeep  阅读(273)  评论(0)  编辑  收藏  举报