PAT A1046 Shortest Distance (20 分)
题目提交一直出现段错误,经过在网上搜索得知是数组溢出,故将数组设置的大一点
AC代码
#include <cstdio>
#include <algorithm>
#define N 11000
using namespace std;
int main(){
#ifdef ONLINE_JUDGE
#else
freopen("1.txt", "r", stdin);
#endif // ONLINE_JUDGE
int dis[N];
int dis_sum[N] = {0};
int n, times, small, big, sum = 0;;
scanf("%d", &n); //输入点的个数
for(int i = 1; i < n + 1; i++) {//输入点与点之间的距离
scanf("%d", &dis[i]);
sum += dis[i];
dis_sum[i] = sum;
}
/*for(int i = 1; i < n + 1; i++) {
printf("--- %d --- %d ---\n", dis[i], dis_sum[i]);
}*/
scanf("%d", ×);
for(int i = 0; i < times; i++) {
int temp1, temp2, right, left, big, small, shortest;
scanf("%d%d", &left, &right);
//printf("%d %d")
big= max(left, right);
small = min(left, right);
temp1 = dis_sum[big - 1] - dis_sum[small - 1]; //从右开始算的距离
//temp2 = dis_sum[small - 1] + (sum - dis_sum[big - 1]); //从左开始算的距离
temp2 = sum - temp1;
shortest = min(temp1, temp2);
//printf("small:%d---dis_sum[small]:%d---big:%d---dis_sum[big]:%d---temp1:%d---temp2:%d---shortest:%d\n", small, dis_sum[small], big, dis_sum[big], temp1, temp2, shortest);
printf("%d\n", shortest);
}
return 0;
}
吾生也有涯,而知也无涯。