【LeetCode】21 - Merge Two Sorted Lists
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
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Solution 1 : create a new list
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { ListNode *newNode=new ListNode(-1); ListNode *ret=newNode; while(l1 && l2){ if(l1->val <= l2->val){ ret->next=l1; l1=l1->next; }else{ ret->next=l2; l2=l2->next; } ret=ret->next; } if(l1) ret->next=l1; else ret->next=l2; return newNode->next; } };
Solution 2 : recursion
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (l1 == NULL) return l2; if (l2 == NULL) return l1; ListNode *ret = NULL; if (l1->val <= l2->val){ ret = l1; ret->next = mergeTwoLists(l1->next, l2); } else{ ret = l2; ret->next = mergeTwoLists(l1, l2->next); } return ret; }