【LeetCode】202 - Happy Number

Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 12 + 92 = 82
  • 82 + 22 = 68
  • 62 + 82 = 100
  • 12 + 02 + 02 = 1

Solution: 辅助函数;循环计算每位数字的平方和,直到出现结果为1(返回true)或者重复(返回false)

 1 class Solution {
 2 public:
 3     bool isHappy(int n) {
 4         map<int,bool> m;
 5         int ret=sum(n);
 6         while(ret!=1){
 7             if(m[ret]==true)return false;
 8             m[ret]=true;
 9             ret=sum(ret);
10         }
11         return true;
12     }
13     int sum(int n){
14         int ret=0;
15         while(n){
16             ret += (n%10)*(n%10);   //不支持(n%10)^2
17             n /= 10;
18         }
19         return ret;
20     }
21 };

 

posted @ 2015-08-02 21:56  irun  阅读(120)  评论(0编辑  收藏  举报