【离散化】acwing802. 区间和
C++ pair的基本用法总结(整理)_sevenjoin的博客-CSDN博客_c++ pair
for(auto i : v)遍历容器元素 - ostartech - 博客园 (cnblogs.com)
#include <iostream> #include <vector> #include <algorithm> using namespace std; typedef pair<int, int> PII; const int N = 300010; int n, m; int a[N], s[N]; vector<int> alls; vector<PII> add, query; int find(int x) { int l = 0, r = alls.size() - 1; while (l < r) { int mid = l + r >> 1; if (alls[mid] >= x) r = mid; else l = mid + 1; } return r + 1;//返回值从1开始,便于后续求前缀和 } vector<int>::iterator unique(vector<int> &a) { int j = 0; for (int i = 0; i < a.size(); i ++ ) if (!i || a[i] != a[i - 1]) a[j ++ ] = a[i]; // a[0] ~ a[j - 1] 所有a中不重复的数 return a.begin() + j; } int main() { cin >> n >> m; for (int i = 0; i < n; i ++ ) { int x, c; cin >> x >> c; add.push_back({x, c}); alls.push_back(x); } for (int i = 0; i < m; i ++ ) { int l, r; cin >> l >> r; query.push_back({l, r}); alls.push_back(l); alls.push_back(r); } // 去重 sort(alls.begin(), alls.end()); alls.erase(unique(alls), alls.end()); // 处理插入 for (auto item : add) { int x = find(item.first); a[x] += item.second; } // 预处理前缀和 for (int i = 1; i <= alls.size(); i ++ ) s[i] = s[i - 1] + a[i]; // 处理询问 for (auto item : query) { int l = find(item.first), r = find(item.second); cout << s[r] - s[l - 1] << endl; } return 0; } 作者:yxc 链接:https://www.acwing.com/activity/content/code/content/40105/ 来源:AcWing 著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。
也可以这样:
#include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<=b;i++) using namespace std; const int N=3e5+10; typedef pair<int,int> PII; int a[N],s[N]; vector<int> alls; vector<PII> add,query; int find(int x){ int l=0,r=alls.size()-1; while(l<r){ int mid=l+r>>1; if(alls[mid]>=x) r=mid; else l=mid+1; } return r+1; } int main(){ int n,m,x,c,l,r; cin>>n>>m; rep(i,0,n-1){ cin>>x>>c; add.push_back({x,c}); alls.push_back(x); } rep(i,0,m-1){ cin>>l>>r; query.push_back({l,r}); alls.push_back(l); alls.push_back(r); } sort(alls.begin(),alls.end()); alls.erase(unique(alls.begin(),alls.end()),alls.end());//改为使用自带库函数unique for(auto item:add){ int x=find(item.first); a[x]+=item.second; } rep(i,1,alls.size()) s[i]=s[i-1]+a[i]; for(auto item:query){ int l=find(item.first),r=find(item.second); cout<<s[r]-s[l-1]<<endl; } return 0; }
Keep it simple and stupid
【推荐】还在用 ECharts 开发大屏?试试这款永久免费的开源 BI 工具!
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步