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LeetCode-Word Search

Given a 2D board and a word, find if the word exists in the grid.

The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be used more than once.

For example,
Given board =

[
  ['A','B','C','E'],
  ['S','F','C','S'],
  ['A','D','E','E']
]
word = "ABCCED", -> returns true,
word = "SEE", -> returns true,
word = "ABCB", -> returns false.
public class Solution {
    public boolean exist(char[][] board, String word) {
        
        boolean result=false;
        
        int m=board.length;
        int n=board[0].length;
        
        for(int i=0; i<m ; i++){
            for(int j=0; j<n; j++){
                if(dfs(board, word, i, j, 0)){
                    result=true;
                }
            }
        }
        return result;
    }
    
    public boolean dfs(char[][] board, String word, int i, int j, int k){
        int m = board.length;
        int n = board[0].length;
        
        if(i<0 || j<0 || i>=m || j>=n){
            return false;
        }
        if(board[i][j] == word.charAt(k)){
            char temp = board[i][j];
            board[i][j]='#';
            if(k==word.length()-1){
                return true;
            }
            else if(dfs(board, word, i-1, j, k+1) || dfs(board, word, i+1, j, k+1) || dfs(board, word, i, j-1, k+1) || dfs(board, word, i, j+1, k+1)){
                return true;
            }
            board[i][j]=temp;
            
        }
        return false;
    }
}

 

class Solution {
    public boolean exist(char[][] board, String word) {
        for (int r = 0; r < board.length; r++) {
            for (int c = 0; c < board[0].length; c++) {
                if (helper(board, r, c, 0, word)){
                    return true;
                }
            }
        }
        return false;
    }
    public boolean helper(char[][] board, int r, int c, int d, String word) {
        // termination condition
        if (r < 0 || r >= board.length || c < 0 || c >= board[0].length) {
            return false;
        }
        if (board[r][c] > 'z' || board[r][c] < 'A') {
            return false;
        }
        if (board[r][c] != word.charAt(d)) {
            return false;
        }
        if(d == word.length()-1) {
            return true;
        }
        char temp = board[r][c];
        board[r][c] = '#';
        boolean found = false;
        if (helper(board, r-1, c, d+1, word) || helper(board, r+1, c, d+1, word) || helper(board, r, c-1, d+1, word) || helper(board, r, c+1, d+1, word))
        {
            found = true;
        }
        board[r][c] = temp;
        return found;   
    }
}

 

posted on 2016-10-05 00:07  IncredibleThings  阅读(97)  评论(0编辑  收藏  举报