P9147 签到题

令 $f_i,g_i$ 分别为以 $i$ 结尾的最长序列，以 $i$ 开始的最长序列，答案为 $max\{f_i+1,g_i+1,[a_{i-1}+1⩽a_{i+1}-1]\ast (f_{i-1}+1+g_{i+1})\}$。

#include <iostream>
using namespace std;
const int N = 1000010;
int n;
int a[N];
int f[N],g[N];
int main ()  {
	cin >> n;
	for (int i = 1;i <= n;i++) cin >> a[i];
	f[1] = 1;
	for (int i = 2;i <= n;i++) {
		f[i] = 1;
		if (a[i - 1] < a[i]) f[i] = max (f[i],f[i - 1] + 1);
	}
	g[n] = 1;
	for (int i = n - 1;i >= 1;i--) {
		g[i] = 1;
		if (a[i] < a[i + 1]) g[i] = max (g[i],g[i + 1] + 1);
	}
	int ans = 0;
	for (int i = 1;i <= n;i++) {
		ans = max (ans,max (f[i] + 1,g[i] + 1));
		if (a[i - 1] + 1 <= a[i + 1] - 1) ans = max (ans,f[i - 1] + 1 + g[i + 1]);
	}
	cout << min (ans,n) << endl;
	return 0;
}