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摘要: You have some number of sticks with positive integer lengths. These lengths are given as an array sticks, where sticks[i] is the length of the ith sti 阅读全文
posted @ 2021-08-29 03:33 苗妙苗 阅读(51) 评论(0) 推荐(0) 编辑
摘要: You are given two string arrays username and website and an integer array timestamp. All the given arrays are of the same length and the tuple [userna 阅读全文
posted @ 2021-08-29 02:55 苗妙苗 阅读(38) 评论(0) 推荐(0) 编辑
摘要: There are n cities labeled from 1 to n. You are given the integer n and an array connections where connections[i] = [xi, yi, costi] indicates that the 阅读全文
posted @ 2021-08-29 01:45 苗妙苗 阅读(61) 评论(0) 推荐(0) 编辑
摘要: Given the root of a binary tree, return the maximum average value of a subtree of that tree. Answers within 10-5 of the actual answer will be accepted 阅读全文
posted @ 2021-08-29 00:52 苗妙苗 阅读(98) 评论(0) 推荐(0) 编辑
摘要: There is a ball in a maze with empty spaces (represented as 0) and walls (represented as 1). The ball can go through the empty spaces by rolling up, d 阅读全文
posted @ 2021-08-28 09:36 苗妙苗 阅读(35) 评论(0) 推荐(0) 编辑
摘要: You have a graph of n nodes. You are given an integer n and an array edges where edges[i] = [ai, bi] indicates that there is an edge between ai and bi 阅读全文
posted @ 2021-08-28 08:46 苗妙苗 阅读(41) 评论(0) 推荐(0) 编辑
摘要: 1、不用spring boot的选择 name, age, dept list 2、lambda排序List.sort(employee, (a, b) -> ((a.name.compareTo(b.name)) && (a.age.compareTo(b.age)))); class Examp 阅读全文
posted @ 2021-08-28 05:21 苗妙苗 阅读(31) 评论(0) 推荐(0) 编辑
摘要: https://drive.google.com/drive/folders/1zQ2BRLQJnoMaMjwbOe8Vt5qNtCJwKraV?usp=sharing 怎么又问出来这么多不会的啊!怒了!我还是图样图森破…… 通过infosys在apple做了九年合同工,看来这两家公司的关系不是一般 阅读全文
posted @ 2021-08-27 01:07 苗妙苗 阅读(26) 评论(0) 推荐(0) 编辑
摘要: https://drive.google.com/drive/folders/1o-ZkaRqUd6KtY455-bNGizDuLf5ymAx2?usp=sharing 阅读全文
posted @ 2021-08-26 04:52 苗妙苗 阅读(85) 评论(0) 推荐(0) 编辑
摘要: synchronization是啥,我说了一点不同步会怎么样同步到底是啥分布式是啥,举个例子你现在的应用难道是单线程的吗(这我还真不知道。。蒙蔽了。。) 合作的单词:cooperate 修房顶的把我吵无语了。。下次选个安静的环境啊 然后我问你们组的业务,就根本懒得跟我说话的那种。 嚣张又没礼貌的臭烙 阅读全文
posted @ 2021-08-25 04:31 苗妙苗 阅读(32) 评论(0) 推荐(0) 编辑
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