搜索旋转排序数组 II
跟进“搜索旋转排序数组”,假如有重复元素又将如何?
一句话思路:不能二分,因为复杂度是n
eg全是0,找一个1
![](https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif)
class Solution { public boolean search(int[] nums, int target) { int i; if (nums.length == 0 || nums == null) { return false; } for (i = 0; i < nums.length ; i++) { if (nums[i] == target) { return true; } } return false; } }