代码改变世界

西尔排序

2011-07-10 11:28  卫佳  阅读(226)  评论(0编辑  收藏  举报

package Utils.Sort; 

*希尔排序,要求待排序的数组必须实现Comparable接口

public class ShellSort implements SortStrategy

{private int[] increment;

       *利用希尔排序算法对数组obj进行排序

              public void sort(Comparable[] obj)

       {if (obj == null)

              {throw new NullPointerException("The argument can not be null!");

              } 

 //初始化步长Titanium Optical Frame

              initGap(obj);

  //步长依次变化(递减)

              for (int i = increment.length - 1 ;i >= 0 ;i-- )

              {int step = increment[i];                     

                     //由步长位置开始High quality Sunglasses

                     for (int j = step ;j < obj.length ;j++ )

                     {Comparable tmp;

                            //如果后面的小于前面的(相隔step),则与前面的交换

                            for (int m = j ;m >= step ;m = m - step )

                            {if (obj[m].compareTo(obj[m - step]) < 0)

                                   {tmp = obj[m - step];

                                          obj[m - step] = obj[m];

                                          obj[m] = tmp;

                                   }

                               else

                                   {

                                          break;

                                   }

                            }

                     }

              }

       }

       *根据数组的长度确定求增量的公式的最大指数,公式为pow(4, i) - 3 * pow(2, i) + 19 * pow(4, i) - 9 * pow

2, i) + 1

       *@return int[] 两个公式的最大指数

       *@param length 数组的长度

       private int[] initExponent(int length)

       {     int[] exp = new int[2];

              exp[0] = 1;

              exp[1] = -1;//Sunglasses manufacturer

              int[] gap = new int[2];

              gap[0] = gap[1] = 0;

                                   //确定两个公式的最大指数

              while (gap[0] < length)

              {                   exp[0]++;

                     gap[0] = (int)(Math.pow(4, exp[0]) - 3 * Math.pow(2, exp[0]) + 1);                                                                }

exp[0]--;

              while (gap[1] < length)

              {exp[1]++;

                           gap[1] = (int)(9 * Math.pow(4, exp[1]) - 9 * Math.pow(2, exp[1]) + 1);                                                                 }

              exp[1]--;

              return exp;

       }

              private void initGap(Comparable[] obj)

       {            //利用公式初始化增量序列Sunglasses Wholesale

              int exp[] = initExponent(obj.length);

              int[] gap = new int[2];

              increment = new int[exp[0] + exp[1]];             

              //将增量数组由大到小赋值

              for (int i = exp[0] + exp[1] - 1 ;i >= 0 ;i-- )

              {         gap[0] = (int)(Math.pow(4, exp[0]) - 3 * Math.pow(2, exp[0]) + 1); 

                      gap[1] = (int)(9 * Math.pow(4, exp[1]) - 9 * Math.pow(2, exp[1]) + 1);

                     //将大的增量先放入增量数组,这里实际上是一个归并排序

                     //不需要考虑gap[0] == gap[1]的情况,因为不可能出现相等。

                     if (gap[0] > gap[1])

                     {                          increment[i] = gap[0];

                            exp[0]--;

                     }                   else

                     {                          increment[i] = gap[1];

                            exp[1]--;

                     }            }            

                     }

}