摘要：
char num[5] = {'a','b','c','d','e'};void fun1(char** ptr) { *ptr = num;}void fun2(char* ptr) { *ptr = num[2];}int _tmain(int argc, _TCHAR* argv[]){ char* test_ptr = NULL; char test_char; fun1(&test_ptr); fun2(&test_char); return 0;} 阅读全文