Type of 'this' pointer in C++

 

  

  In C++, this pointer is passed as a hidden argument to all non-static member function calls. The type of this depends upon function declaration. If the member function of a class X is declared const, the type of this is const X* (see code 1 below), if the member function is declared volatile, the type of this is volatile X* (see code 2 below), and if the member function is declared const volatile, the type of this is const volatile X* (see code 3 below).

  Code 1

1 #include<iostream>
2 class X 
3 {
4    void fun() const 
5    {
6         // this is passed as hidden argument to fun(). 
7         // Type of this is const X* 
8    }
9 };

 

  Code 2

1 #include<iostream>
2 class X 
3 {
4    void fun() volatile 
5    {
6         // this is passed as hidden argument to fun(). 
7         // Type of this is volatile X* 
8     }
9 };

 

  Code 3

1 #include<iostream>
2 class X 
3 {
4    void fun() const volatile 
5    {
6      // this is passed as hidden argument to fun(). 
7      // Type of this is const volatile X* 
8     }
9 };

 

  补充:

  (1)In an ordinary nonconst member function, the type of this is a const pointer to the class type. We may change the value to which this points but cannot change the address that this holds. In a const member function, the type of this is a const pointer to a const class - type object. We may change neither the object to which this points nor the address that this holds.

  (2)What is the purpose of a volatile member function in C++?【from stackoverflow】

  

 

 

  References:http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1905.pdf

 

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  2013-11-26  09:32:58

posted @ 2013-11-26 09:37  虔诚的学习者  阅读(247)  评论(0编辑  收藏  举报