第八次上机作业
1、编写一个简单程序,要求数组长度为5,分别赋值10,20,30,40,50,在控制台输出该数组的值。(知识点:数组定义和创建、一维数组初始化)[必做题]•
package abc; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub int shuzu[] = new int[]{10,20,30,40,50}; for (int i : shuzu) { System.out.println(i); } } }
2、将一个字符数组的值(neusofteducation)拷贝到另一个字符数组中。(知识点:数组复制) [必做题]•
package abc; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub char[] shuzu = new char[]{'a','b','c','d','o','f','t',}; char[] copy = new char[16]; System.arraycopy(shuzu, 0, copy, 0, shuzu.length); for (char c : copy) { System.out.println(c); } } }
3、给定一个有9个整数(1,6,2,3,9,4,5,7,8)的数组,先排序,然后输出排序后的数组的值。(知识点:Arrays.sort排序、冒泡排序)
package abc; import java.util.Arrays; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub int shuzu[] = new int[]{1,6,2,3,9,4,5,7,8}; Arrays.sort(shuzu); for (int i : shuzu) { System.out.println(i); } } }
4、 输出一个double型二维数组(长度分别为5、4,值自己设定)的值。(知识点:数组定义和创建、多维数组初始化、数组遍历)
package abc; import java.util.Arrays; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub double a[][] = { { 1, 2, 3, 4 }, { 2, 3, 4, 5 }, { 3, 4, 5, 6 }, { 4, 5, 6, 7 }, { 5, 6, 7, 8 } }; for (int i = 0; i < a.length; i++) { for (int j = 0; j < a.length - 1; j++) { System.out.print(a[i][j] + " "); } System.out.println(); } } }
5、 在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。(知识点:数组遍历、数组元素访问) [必做题]?
package abc; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub int a[] = { 18, 25, 7, 36, 13, 2, 89, 63 }; int max = a[0]; int maxidx = 0; for (int i = 0; i < a.length; i++) { if (a[i] > max) { max = a[i]; maxidx = i; } } System.out.println("最大值为" + max + "下标为" + maxidx); } }
作业
6、将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问
package abc; import java.util.Scanner; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); int a[] = new int[5]; for (int i = a.length; i > 0; i--) { a[i - 1] = input.nextInt(); } for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } } }
7. 将一个数组中的重复元素保留一个其他的清零。(知识点:数组遍历、数组元素访问)
package abc; import java.util.Scanner; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); int a[] = new int[5]; for (int i = 0; i < a.length; i++) { a[i] = input.nextInt(); } for (int i = 0; i < a.length - 1; i++) { for (int j = i + 1; j < a.length; j++) { if (a[i] == a[j]) { a[j] = 0; } } } for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } } }
8、给定一维数组{ -10,2,3,246,-100,0,5},计算出数组中的平均值、最大值、最小值。(知识点:数组遍历、数组元素访问)
package abc; import java.util.Scanner; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub int a[] = { -10, 2, 3, 246, -100, 0, 5 }; int max = a[0], min = a[0]; int sum = 0; double avg = 0; for (int i = 0; i < a.length; i++) { sum += a[i]; avg = sum / 7; if (a[i] > max) { max = a[i]; } if (a[i] < min) { min = a[i]; } } System.out.println("平均值为" + avg); System.out.println("最大值为" + max); System.out.println("最小值为" + min); } }
9、使用数组存放裴波那契数列的前20项 ,并输出 1 1 2 3 5 8 13 21
package abc; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub int a[] = new int[20]; a[0] = 1; int x = 1; int y = 1; int z = 1; for (int i = 0; i < a.length; i++) { a[i] = z; z = x + y; x = y; y = z; } for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } } }
10、生成一个长度为10的随机整数数组(每个数都是0-100之间),输出,排序后,再输出
package abc; import java.util.Arrays; import java.util.Random; public class ysc { public static void main(String[] args) { // TODO Auto-generated method stub Random r = new Random(); int a[] = new int[10]; for (int i = 0; i < a.length; i++) { a[i] = r.nextInt(100); System.out.println(a[i]); } Arrays.sort(a); System.out.println("排序后输出"); for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } } }