摘要: class Solution { public: int numIslands(vector>& grid) { if (grid.empty() || grid[0].empty()) return 0; int count=0; int m = grid.size(), n = grid[0].size(); ... 阅读全文
posted @ 2018-12-28 23:59 keep! 阅读(151) 评论(0) 推荐(0) 编辑
摘要: //关键就是把每一层的节点数记下来,当循环完当层节点数再输出队列的最后一位耗时4ms class Solution { public: vector rightSideView(TreeNode* root) { vector res; if(!root)return res; queue q; q... 阅读全文
posted @ 2018-12-28 01:08 keep! 阅读(107) 评论(0) 推荐(0) 编辑
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