for里面是采用setInterval遍历二维数组，for循环到最后一个数的时候，才执行setInterval的问题解决
点击播放看效果
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<head>
<meta charset="UTF-8">
<meta name="viewport"
content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">
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<title>for里面是采用setInterval遍历二维数组，for循环到最后一个数的时候，才执行setInterval的问题解决</title>
</head>
<body>
<button id="play">播放</button>
<script>
var sumPath=[
{
RowKey:"LNBSCB3F2FD11327120190327091134",
point:[
{Longitude: "104.074027",Latitude:"30.707441"},
{Longitude: "104.109422", Latitude: "30.669311"},
{Longitude: "104.108675", Latitude: "30.665402"},
{Longitude: "104.108667", Latitude: "30.665388"}]},
{
RowKey:"LNBSCB3F2FD11327120190327103555",
point:[
{Longitude: "104.113186", Latitude: "30.663265"},
{Longitude: "104.114061", Latitude: "30.663335"},
{Longitude: "104.11468", Latitude: "30.663531"},
{Longitude: "104.115255", Latitude: "30.663612"},
{Longitude: "104.11565", Latitude: "30.663767"}
]
}];
// 怎么按顺序遍历二维数组 ，如果是for里面是一个setInterval，则到for循环到最后一个数的时候，才执行setInterval。 需要用2个setInterval来解决，setInterval是异步的，里面却是同步的
document.getElementById("play").addEventListener("click",function () {
firstTraverse();
});
var firstIndex=0;// 第一层数组的index
var secondIndex=0;// 第二层数组的index
// 第一层的遍历
function firstTraverse () {
var firstInterval=setInterval(function () {
clearInterval(firstInterval);
if(firstIndex<sumPath.length){
var point=sumPath[firstIndex].point;
secondTraverse(point);// 第二层数组传过去
console.log("第一层的index："+firstIndex);
}
},1000)
}
// 第二层的遍历
function secondTraverse (point) {
var secondInterval=setInterval(function () {
if(secondIndex<point.length){
console.log("第二层的index："+secondIndex);
drivePath();
}else {
clearInterval(secondInterval);// 要清的是第二个定时器
secondIndex=0;
firstIndex++;
firstTraverse();// 从第一个开始重新调用
return;
}
secondIndex++;
},1000)
}
// 划线
function drivePath() {
}
</script>
</body>
</html>
