工作常用到的sql语句
产生行号
RowId name address
1 ike beijing
2 ike2 shanghai
3 ike3 suzhou
4 ike3 suzhou
删除重复的数据
(select row_number() over(order by name asc) as RowId,* from Student)
delete from [sqlRowNumber] where RowId=3
列出父级的所有子级
例如:公司部门的数据
table:Department
SubDepartment ParentDepartment
A1 A
A21 A1
A31 A21
5.
select TabReportChange_date,SUM(TabReportChange_subtotal),SUM(TabReportChange_discount),
SUM(TabReportChange_tax),SUM(TabReportChange_total),
CASE
WHEN TabReportChange.TabReportChange_date = '2015-06-01' THEN '0Mon'
WHEN TabReportChange.TabReportChange_date = '2015-06-02' THEN '1Tue'
WHEN TabReportChange.TabReportChange_date = '2015-06-03' THEN '2Wed'
WHEN TabReportChange.TabReportChange_date = '2015-06-04' THEN '3Thu'
WHEN TabReportChange.TabReportChange_date = '2015-06-05' THEN '4Fri'
WHEN TabReportChange.TabReportChange_date = '2015-06-06' THEN '5Sat'
WHEN TabReportChange.TabReportChange_date = '2015-06-07' THEN '6Sun'
ELSE NULL END AS 'C',count(*) AS count
from TabReportChange
left JOIN (select TabReport_num,TabReport_status from TabReport where TabReport_status = 0 GROUP BY TabReport_status) T2 ON T2.[TabReport_num] = [TabReportChange].[TabReportChange_num]
where (TabReportChange.TabReportChange_date >= '2015-06-01' AND TabReportChange.TabReportChange_date <= '2015-06-07') and T2.TabReport_status=0
6. insert into 值中某一个从数据表取一个字段值
insert into TabTax(company_num,TabTax_num,TabTax_name,TabTax_value) select '1000',max(tabtax_num)+1,'aaa','9.6' from tabtax where company_num='1000'
INSERT INTO file_detail(file_id,category_id,create_time)SELECT id,
(SELECT id FROM file_category WHERE category_text='CCCC'),'2021/01/08 15:35:20' FROM file_list WHERE file_path='D:/Project/Qt/1.txt'
7.sqlite 日期时间函数
select date(A.add_time),time(A.add_time),A.pos_no,B.product_name,A.weight,A.sale_price,A.sale_total,A.add_user from tab_sale A left join tab_product B on A.product_num=B.product_num where A.add_time>='2016-02-18 00:00' and A.add_time<='2016-02-18 23:29'
8.组合查询
红色语句是子查询
select A.product_num,B.product_name,sum(A.sale_total),C.customers,count(A.product_num),sum(A.weight) from tab_sale A left join tab_product B on A.product_num=B.product_num
left join (select product_num,count(product_num)as customers from (select product_num,list_num from tab_sale group by list_num,product_num) group by product_num) C on A.product_num=C.product_num
group by A.product_num