[sql]外键操作

主键

1个字段为主键

create table person(
	nid int not null auto_increment primary key,
	name varchar(40) not null,
	email varchar(40) not null,
	partment_nid int not null
);
create table person(
	nid int not null auto_increment primary key,
	name varchar(40) not null,
	email varchar(40) not null,
	partment_nid int not null,
	PRIMARY KEY (nid)
);

2个字段同时为主键

- 即nid&name不能同时相同

nid    name
1       maotai
1       maotai # 第一条和第二条重复被限制
2       maotai


create table person(
	nid int not null auto_increment,
	name varchar(40) not null,
	email varchar(40) not null,
	partment_nid int not null,
	PRIMARY KEY (nid, name)
);
- 这种是没办法被识别的, 也体现了PRIMARY KEY ()写法的用途.

create table person(
	nid int not null auto_increment primary key,
	name varchar(40) not null primary key,
	email varchar(40) not null,
	partment_nid int not null,
);

外键

- partment
1,重复太多
2,太占空间

person:
nid    name    email    partment
1      maotai  1@qq.com 毛台科技创新公司-开发组
2      maotai  1@qq.com 毛台科技创新公司-技术部
3      maotai  1@qq.com 毛台科技创新公司-测试组
4      maotai  1@qq.com 毛台科技创新公司-测试组

- partment:(字典表)
nid     part
1       毛台科技创新公司-开发组
2       毛台科技创新公司-测试组


- person:
nid    name    email    partment # 外键: 关联另一张表的主键
1      maotai  1@qq.com 1
2      maotai  1@qq.com 1
3      maotai  1@qq.com 2
4      maotai  1@qq.com 2

- 默认2张表是没关系的,需要使用外键关联

create table partment(
    nid int not null auto_increment primary key,
    part varchar(40) not null
);

create table person(
	nid int not null auto_increment,
	name varchar(40) not null,
	email varchar(40) not null,
	partment_nid int not null,
	PRIMARY KEY (nid),
	CONSTRAINT fk_person_to_partment FOREIGN key (partment_nid) REFERENCES partment(nid)
);

insert into partment (part) values ('CEO');
insert into partment (part) values ('COO');
insert into partment (part) values ('CFO');

insert into person(name,email,partment_nid)values('maotai','1@qq.com',1);
insert into person(name,email,partment_nid)values('maotai2','2@qq.com',2);
insert into person(name,email,partment_nid)values('maotai3','3@qq.com',2); # partment_nid值必须是partment表里有的.否则报错

alter table person drop foreign key fk_person_to_partment;

- 先删除外键, 然后添加就不报错了
insert into person(name,email,partment_nid)values('maotai2','2@qq.com',4);
- 删除外键
alter table person drop foreign key fk_person_to_partment;

- 新建外键
alter table person add constraint fk_person_to_partment foreign key(partment_nid) references partment(nid);

连表查询(外键)

通过select方式连接

- 找到CEO部门的所有人员的信息

# 先找所有人name
select name from person;

# 找出id为1的name
select name from person where partment_nid in (1); # 过滤id为1的数据

# 找出ceo的id
select nid from partment where part='CEO'; # 得到CEO的id

# 找出ceo的名字
select name from person where partment_nid in (select nid from partment where part='CEO';);

通过join方式连接

select * from person left join partment on person.partment_nid = partment.nid;

select * from person left join partment on person.partment_nid = partment.nid where partment.part = 'CEO';

select person.name from person left join partment on person.partment_nid = partment.nid where partment.part = 'CEO';

join的3种方式

left join(最常用)

A left join B on 条件
    以A为主
    将A中所有字段罗列
    B,则显示与A对应的数据

select * from person left join partment on person.partment_nid = partment.nid;

B left join A on 条件
    以B为主
select * from partment left join person on person.partment_nid = partment.nid;

right join

- 以下效果一样: A left join B == B right join A

select * from partment left join person on person.partment_nid = partment.nid;

select * from person right join partment on person.partment_nid = partment.nid;

inner join(自动去掉脏数据)

-   自动忽略为建立关系的数据
select * from person inner join partment on person.partment_nid = partment.nid;
create table color(
nid int not null auto_increment primary key,
color varchar(30) not null
);

insert into color(color)values('pink');
insert into color(color)values('red');
insert into color(color)values('yellow');


alter table person add color_nid int(4) after partment_nid;


alter table person add CONSTRAINT fk_person_to_color FOREIGN key (color_nid) REFERENCES color(nid);

join多个表

- 是CEO且喜欢pink色的
select * from person 
left join partment on person.partment_nid = partment.nid
LEFT JOIN color on person.color_nid = color.nid

select * from person 
left join partment on person.partment_nid = partment.nid
LEFT JOIN color on person.color_nid = color.nid
where partment.part = 'CEO' and color.color='pink';

- 自定义列明

select
person.name as pname,
partment.part as cp,
color.color as cl
from person 
left join partment on person.partment_nid = partment.nid
LEFT JOIN color on person.color_nid = color.nid
where partment.part = 'CEO' and color.color='pink';

- man
nid    name    配偶
1      aaron    1
2      boby     2
3      lanny    1

- woman
nid    name    配偶
1      emy      1
2      sara     1
3      zara     1

多对多关系

- 设计第三张关系表,为了逃避不确定因素

- man
nid    name
1      aaron
2      boby
3      lanny

- woman
nid    name
1      emy
2      sara
3      zara

- 关系表
男id    女id
1        1
1        2
2        2
3        3
- 本质上是两个外键

create table man(
nid int auto_increment not null primary key,
name varchar(40) not null
);

create table woman(
nid int auto_increment not null primary key,
name varchar(40) not null
);



create table relationship(
nid int auto_increment not null primary key,
man_nid int not null,
woman_nid int not null,
constraint fk_relationship_to_mannid FOREIGN key (man_nid) REFERENCES man(nid),
constraint fk_relationship_to_womannid FOREIGN key (woman_nid) REFERENCES woman(nid)
);

insert into man(name)values('aaron');
insert into woman(name)values('aaron');

insert into relationship(man_nid,woman_nid)values(1,1);
select nid from man where name='aaron';

select man_nid from relationship where man_nid = (select nid from man where name='aaron');
select * from relationship
LEFT JOIN man on relationship.man_nid = man.nid
LEFT JOIN woman on relationship.woman_nid = woman.nid;

select * from relationship
LEFT JOIN man on relationship.man_nid = man.nid
LEFT JOIN woman on relationship.woman_nid = woman.nid
where man.name = 'aaron';

posted @ 2018-04-15 16:36  mmaotai  阅读(266)  评论(0编辑  收藏  举报