29.2、形态学---综合实例2

目标要求：通过形态学相关操作，求出右边4个IC引脚的个数。

 

程序：

 

 

 

*读入图像，并把它转换为灰度图

read_image (Image000513532, 'F:/Halcon学习/7、测试图片/000513532.jpg')

rgb1_to_gray (Image000513532, GrayImage)

*设置ROI减少图像处理篇幅

gen_rectangle1 (ROI_0, 36.4579, 780.639, 565.239, 1020.27)

reduce_domain (GrayImage, ROI_0, ImageReduced)

*阈值分割

threshold (ImageReduced, Regions, 0, 83)

 

*连通性分析，并进行填补空洞

connection (Regions, ConnectedRegions)

fill_up (ConnectedRegions, RegionFillUp)

 

*开运算

opening_circle (RegionFillUp, RegionOpening, 3)

*连通性，面积筛选

connection (RegionOpening, ConnectedRegions1)

select_shape (ConnectedRegions1, SelectedRegions, 'area', 'and', 4159.99, 6167)

 

*最小外接矩形，并创建出来

smallest_rectangle1 (SelectedRegions, Row1, Column1, Row2, Column2)

gen_rectangle1 (Rectangle, Row1, Column1, Row2, Column2)

 

*排序并计算中心点，便于下面打印字体到图像上

sort_region (Rectangle, Rectangle, 'first_point', 'true', 'column')

area_center (Rectangle, Area, Row, Column)

 

*膨胀，膨胀后结果与没膨胀前做差集，获取得引脚部分区域

dilation_rectangle1 (Rectangle, RegionDilation, 16, 1)

difference (RegionDilation, Rectangle, RegionDifference)

*把引脚从图像中分割出来

add_channels (RegionDifference, GrayImage, GrayRegions)

*计算有多少个ic

count_obj (GrayRegions, Number)

 

dev_clear_window ()

dev_display (Image000513532)

dev_update_window ('off')

 

*循环遍历每个ic引脚部分区域

for Index := 1 to Number by 1

*获得引脚部分图像，并阈值分割

select_obj (GrayRegions, ObjectSelected, Index)

threshold (ObjectSelected, Regions1, 112, 255)

 

*开运算把引脚粘连部分分开，-----选取矩形宽度高度分别为5,1因为宽度方向要去除更多，才能分开粘连部分

opening_rectangle1 (Regions1, RegionOpening1, 5, 1)

*连通性分析

connection (RegionOpening1, ConnectedRegions2)

dev_display (ConnectedRegions2)

*计算引脚个数

count_obj (ConnectedRegions2, Number1)

*打印个数到图像上

disp_message (3600, Number1, 'image', Row[Index-1]-10, Column[Index-1]-10, 'yellow', 'false')

 

endfor

 

 

 

最终效果：