Mujin Contest 2017 B. Row to Column

题目大意

给一个$n\times n$的棋盘,上面有黑白,每次任意取一行一列,把列染成行的颜色,问最少多少次让棋盘全黑。

简要题解

全黑列不要动,那么非全黑列在构造出全黑行之前显然是不增不减的(除非你主动去染全黑的列),然后构造出一个全黑行,然后去染就好。

比赛时就是这么想的,然而构造全黑行时脑子进了点水。。

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 namespace my_header {
 4 #define pb push_back
 5 #define mp make_pair
 6 #define pir pair<int, int>
 7 #define vec vector<int>
 8 #define pc putchar
 9 #define clr(t) memset(t, 0, sizeof t)
10 #define pse(t, v) memset(t, v, sizeof t)
11 #define bl puts("")
12 #define wn(x) wr(x), bl
13 #define ws(x) wr(x), pc(' ')
14     const int INF = 0x3f3f3f3f;
15     typedef long long LL;
16     typedef double DB;
17     inline char gchar() {
18         char ret = getchar();
19         for(; (ret == '\n' || ret == '\r' || ret == ' ') && ret != EOF; ret = getchar());
20         return ret; }
21     template<class T> inline void fr(T &ret, char c = ' ', int flg = 1) {
22         for(c = getchar(); (c < '0' || '9' < c) && c != '-'; c = getchar());
23         if (c == '-') { flg = -1; c = getchar(); }
24         for(ret = 0; '0' <= c && c <= '9'; c = getchar())
25             ret = ret * 10 + c - '0';
26         ret = ret * flg; }
27     inline int fr() { int t; fr(t); return t; }
28     template<class T> inline void fr(T&a, T&b) { fr(a), fr(b); }
29     template<class T> inline void fr(T&a, T&b, T&c) { fr(a), fr(b), fr(c); }
30     template<class T> inline char wr(T a, int b = 10, bool p = 1) {
31         return a < 0 ? pc('-'), wr(-a, b, 0) : (a == 0 ? (p ? pc('0') : p) : 
32             (wr(a/b, b, 0), pc('0' + a % b)));
33     }
34     template<class T> inline void wt(T a) { wn(a); }
35     template<class T> inline void wt(T a, T b) { ws(a), wn(b); }
36     template<class T> inline void wt(T a, T b, T c) { ws(a), ws(b), wn(c); }
37     template<class T> inline void wt(T a, T b, T c, T d) { ws(a), ws(b), ws(c), wn(d); }
38     template<class T> inline T gcd(T a, T b) {
39         return b == 0 ? a : gcd(b, a % b); }
40     template<class T> inline T fpw(T b, T i, T _m, T r = 1) {
41         for(; i; i >>= 1, b = b * b % _m)
42             if(i & 1) r = r * b % _m;
43         return r; }
44 };
45 using namespace my_header;
46 
47 int a[555][555];
48 
49 int main() {
50 #ifdef lol
51     freopen("b.in", "r", stdin);
52     freopen("b.out", "w", stdout);
53 #endif
54 
55     int n = fr(), c = n, t = 0;
56     for (int i = 1; i <= n; ++i)
57         for (int j = 1; j <= n; ++j) {
58             a[i][j] = gchar();
59             if (a[i][j] == '#')
60                 t = 1;
61         }
62     if (!t) {
63         puts("-1");
64         return 0;
65     }
66     for (int i = 1; i <= n; ++i) {
67         int flg = true;
68         for (int j = 1; j <= n; ++j) {
69             if (a[j][i] == '.')
70                 flg = false;
71         }
72         c -= flg;
73     }
74     int ans = 2 * n;
75     for (int i = 1; i <= n; ++i) {
76         int x = 0;
77         for (int j = 1; j <= n; ++j)
78             if (a[i][j] == '.')
79                 ++x;
80         int flg = 1;
81         for (int j = 1; j <= n; ++j)
82             if (a[j][i] == '#')
83                 flg = 0;
84         x += flg;
85         ans = min(ans, x + c);
86     }
87     wt(ans);
88 
89     return 0;
90 }
View Code

 

posted @ 2017-03-06 17:38  ichneumon  阅读(201)  评论(0编辑  收藏  举报