代码改变世界

C# 程序启动其他进程程序

2014-07-14 11:52  Spring.Guo  阅读(8453)  评论(0编辑  收藏  举报

1  启动一个独立进程,需要用到的命名空间是:using System.Diagnostics;   进程类是 Process ,进程的相关参数信息类是 ProcessStartInfo

2  等待启动的控制台app代码:

using System;
using System.Threading;
namespace ShowConsoleApp
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("app start!");
            foreach (string item in args)
            {
                Console.WriteLine(" accept a arg that is {0}", item);

                Thread.Sleep(3000);             
            }

            Console.WriteLine("app stop!");
        }
    }
}

3  启动模式:  并行和串行模式,注意比较代码区别。

using System;
using System.Threading;
using System.Diagnostics;

namespace HDTest
{
    class Program
    {
        static void Main(string[] args)
        {           

           for (int i = 0; i < 2; i++)
           {
               //并行: 多个同命实例进程一起执行
               RunMutilInstanceProcess(i);

               //串行,一个进程启动结束后,运行下一个
             //  WaitSonProcess(i);

               Thread.Sleep(2000);

           }

            Console.ReadLine();
        }

        static void RunMutilInstanceProcess(int i)
        {
            string appPath = @"E:\VS2010Code\AppTest\ShowConsoleApp\bin\Debug\ShowConsoleApp.exe";
            ProcessStartInfo process = new ProcessStartInfo();
            process.FileName = appPath;
            process.Arguments = "process " + i.ToString();

            process.UseShellExecute = false;
            process.CreateNoWindow = true;

            process.RedirectStandardOutput = true;
            Process.Start(process);

           // string Result = p.StandardOutput.ReadToEnd();
           // Console.WriteLine("the console app output is {0}", Result);
             Console.WriteLine(" process {0} start", i);
        }

        static void WaitSonProcess(int i)
        {
            Process process = new Process();
            string appPath = @"E:\VS2010Code\AppTest\ShowConsoleApp\bin\Debug\ShowConsoleApp.exe";
            process.StartInfo.FileName = appPath;
            process.StartInfo.Arguments = "process " + i.ToString();

            process.StartInfo.UseShellExecute = false;
            process.StartInfo.CreateNoWindow = true;

            process.StartInfo.RedirectStandardOutput = true;

            // process.StartInfo.WindowStyle = ProcessWindowStyle.Normal;
            // Start the process
            process.Start();

            Console.WriteLine(" process {0} start", i);
            // Wait that the process exits
             process.WaitForExit();

            Console.WriteLine("the process  had exits");

            // Now read the output of the DOS application
            string Result = process.StandardOutput.ReadToEnd();

            Console.WriteLine("the console app output is {0}", Result);
        }
    }
}