C# 程序启动其他进程程序
2014-07-14 11:52 Spring.Guo 阅读(8453) 评论(0) 编辑 收藏 举报1 启动一个独立进程,需要用到的命名空间是:using System.Diagnostics; 进程类是 Process ,进程的相关参数信息类是 ProcessStartInfo
2 等待启动的控制台app代码:
using System;
using System.Threading;
namespace ShowConsoleApp
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("app start!");
foreach (string item in args)
{
Console.WriteLine(" accept a arg that is {0}", item);
Thread.Sleep(3000);
}
Console.WriteLine("app stop!");
}
}
}
3 启动模式: 并行和串行模式,注意比较代码区别。
using System;
using System.Threading;
using System.Diagnostics;
namespace HDTest
{
class Program
{
static void Main(string[] args)
{
for (int i = 0; i < 2; i++)
{
//并行: 多个同命实例进程一起执行
RunMutilInstanceProcess(i);
//串行,一个进程启动结束后,运行下一个
// WaitSonProcess(i);
Thread.Sleep(2000);
}
Console.ReadLine();
}
static void RunMutilInstanceProcess(int i)
{
string appPath = @"E:\VS2010Code\AppTest\ShowConsoleApp\bin\Debug\ShowConsoleApp.exe";
ProcessStartInfo process = new ProcessStartInfo();
process.FileName = appPath;
process.Arguments = "process " + i.ToString();
process.UseShellExecute = false;
process.CreateNoWindow = true;
process.RedirectStandardOutput = true;
Process.Start(process);
// string Result = p.StandardOutput.ReadToEnd();
// Console.WriteLine("the console app output is {0}", Result);
Console.WriteLine(" process {0} start", i);
}
static void WaitSonProcess(int i)
{
Process process = new Process();
string appPath = @"E:\VS2010Code\AppTest\ShowConsoleApp\bin\Debug\ShowConsoleApp.exe";
process.StartInfo.FileName = appPath;
process.StartInfo.Arguments = "process " + i.ToString();
process.StartInfo.UseShellExecute = false;
process.StartInfo.CreateNoWindow = true;
process.StartInfo.RedirectStandardOutput = true;
// process.StartInfo.WindowStyle = ProcessWindowStyle.Normal;
// Start the process
process.Start();
Console.WriteLine(" process {0} start", i);
// Wait that the process exits
process.WaitForExit();
Console.WriteLine("the process had exits");
// Now read the output of the DOS application
string Result = process.StandardOutput.ReadToEnd();
Console.WriteLine("the console app output is {0}", Result);
}
}
}