NYOJ--68
原题链接:http://acm.nyist.net/JudgeOnline/problem.php?pid=68
分析:有向图。
三点顺序
1 #include<stdio.h> 2 int main() 3 { 4 int x1,y1,x2,y2,x3,y3,p;long s; 5 while(scanf("%d%d%d%d%d%d",&x1,&y1,&x2,&y2,&x3,&y3)==6) 6 { 7 if(x1==0&&y1==0&&x2==0&&y2==0&&x3==0&&y3==0)break; 8 s=x1*y2+x3*y1+x2*y3-x3*y2-x1*y3-x2*y1; 9 if(s>0)p=0; 10 else p=1; 11 printf("%d\n",p); 12 } 13 return 0; 14 } 15 16