java第十次作业

1.利用接口实现动态的创建对象[选做题] • 5.1 创建4个类: • 苹果 • 香蕉 • 葡萄 • 园丁 • 5.2 在三种水果的构造方法中打印一句话. • 以苹果类为例
package rrrr;
 
public interface Fruit {
 
        class apple implements Fruit {
 
            public apple() {
 
                System.out.println("创建了一个苹果类对象");
 
            }
 
        }
 
        class grape implements Fruit {
 
            public grape() {
 
                System.out.println("创建了一个葡萄类的对象");
 
            }
 
        }
 
        class banana implements Fruit {
 
            public banana() {
 
                System.out.println("创建了一个香蕉类的对象");
 
            }
 
        }
 
    }
package rrrr;
 
import java.util.Scanner;
 
import rrrr.Fruit.apple;
 
import rrrr.Fruit.grape;
 
import rrrr.Fruit.banana;
 
public class Gardener {
 
    public static void main(String[] args) {
        // TODO Auto-generated method stub
 
        Gardener g = new Gardener();
 
        g.create();
 
    }
 
    public Fruit create() {
 
        Scanner sc = new Scanner(System.in);
 
        System.out.println("请输入水果名称");
 
        String name = sc.next();
 
        Fruit F = null;
 
        if (name.equals("苹果")) {
 
            F = new apple();
 
        } else if (name.equals("香蕉")) {
 
            F = new banana();
 
        } else if (name.equals("葡萄")) {
 
            F = new grape();
 
        }
 
        return F;
 
    }
 
}

输入6位密码,再次输入密码,如果不够6位,提示,位数不对,如果两次不一致,提示两次密码不一致

package ooo;
 
import java.util.Scanner;
 
public class Wyy {
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner sc = new Scanner(System.in);
        System.out.println("请输入您的密码");
        String pass1 = sc.next();
        System.out.println("请再次输入密码");
        String pass2 = sc.next();
        if (pass1.length() > 0 && pass1.length() < 6) {
            System.out.println("位数不足");
            } else if (!pass1.equals(pass2)) {
                System.out.println("两次密码不一致");
                }
        }
 
}

2.输入一个字符串,如果开头是ok并且包含no,那么输入错误

import java.util.Scanner;
public class Wyy {
    static Scanner sc = new Scanner(System.in);
    public static void shuru() {
        System.out.println("请输入一段字符");
        String string = sc.next();
        if (string.startsWith("ok") && string.contains("no")) {
            System.out.println("输入错误");
        } else {
            System.out.println("输入正确");
        }
        System.out.println("是否从新输入?Y/N");
        if (sc.next().equalsIgnoreCase("y")) {
            panduan();
        } else {
            System.out.println("谢谢使用");
        }
    }
    public static void panduan() {
        shuru();
    }
}package ooo;
public class ttt {
        public static void main(String[] args) {
    // TODO Auto-generated method stub
            Wyy w = new Wyy();
            w.shuru();
        }
    }

 

输入三个单词,组合成pascal命名法的字符串

输入:STU

manage

system

输出

StuManageSystem 

可以考虑:charAt,touppercase,tolowercase等等。字符串连接+ concat

import java.util.Scanner;
 
public class Wyy {
 
     
 
    public static void main(String[] args) {
    // TODO Auto-generated method stub
 
    Scanner sc = new Scanner(System.in);
 
    System.out.println("请输入第一段字符串");
 
    String s1 = sc.next();
 
    String string0 = s1.substring(0, 1);
 
    String string1 = s1.substring(1, 3).toLowerCase();
 
    System.out.println("请输入第二段字符串");
 
    String s2 = sc.next();
 
    String string2 = s2.substring(0, 1).toUpperCase();
 
    String string3 = s2.substring(1, 6);
 
    System.out.println("请输入第三段字符串");
 
    String s3 = sc.next();
 
    String string4 = s3.substring(0, 1).toUpperCase();
 
    String string5 = s3.substring(1, 6);
 
    System.out.println(string0 + string1 + string2 + string3 + string4 + string5);
 
    }
 
    }

 

posted @ 2023-06-30 13:14  owxd  阅读(9)  评论(0编辑  收藏  举报