棋盘覆盖问题

//使用分治策略,设计解棋盘覆盖问题的简洁算法

#define SIZE 512
static int tile=0;//L型骨牌号
int Board[SIZE][SIZE];

void ChessBoard(int tr,int tc,int dr,int dc,int size)
{
if(size==1) return;
int t=tile++,s=size/2;//分割棋盘

//覆盖左上角子棋盘
if(dr<tr+s&&dc<tc+s)

ChessBoard(tr,tc,dr,dc,s);
else{ //此棋盘中无特殊方格
//用t号L型骨牌覆盖右下角
Board[tr+s-1][tc+s-1]=t;

ChessBoard(tr,tc,tr+s-1,tc+s-1,s);
}

//覆盖右上角子棋盘
if(dr<tr+s&&dc>tc+s)

ChessBoard(tr,tc+s,dr,dc,s);
else{
Board[tr+s-1][tc+s]=t;
ChessBoard(tr,tc+s,tr+s-1,tc+s,s);
}

//覆盖左下角子棋盘
if(dr>tr+s&&dc<tc+s)

ChessBoard(tr+s,tc,dr,dc,s);
else{
Board[tr+s][tc+s-1]=t;
ChessBoard(tr+s,tc,tr+s,tc+s-1,s);
}

//覆盖右下角子棋盘
if(dr>tr+s&&dc>tc+s)

ChessBoard(tr+s,tc+s,dr,dc,s);
else{
Board[tr+s][tc+s]=t;
ChessBoard(tr+s,tc+s,tr+s,tc+s,s);
}

}


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posted @ 2012-02-16 18:32  苍术厚朴  阅读(219)  评论(0编辑  收藏  举报