easyui tree后台传json处理问题

一、tree json格式

[
    {
        "id": 1,
        "text": "权限管理",
        "iconCls": "icon-feed",
        "checked": false,
        "attributes": {
            "url": "#123"
        },
        "children": [
            {
                "id": 2,
                "text": "用户管理",
                "iconCls": "icon-users",
                "checked": false,
                "attributes": {
                    "url": null
                },
                "state": null
                
            },
            {
                "id": 3,
                "text": "角色管理",
                "iconCls": "icon-users",
                "checked": false,
                "attributes": {
                    "url": null
                },
                "children": [
                    {
                        "id": 10,
                        "text": "角色管理1",
                        "iconCls": "icon-users",
                        "checked": false,
                        "attributes": {
                            "url": null
                        },
                        "state": null
                       
                    }
                ],
                "state": null
                
            },
            {
                "id": 4,
                "text": "菜单管理",
                "iconCls": "icon-users",
                "checked": false,
                "attributes": {
                    "url": "#222"
                },
                "state": null,
                "children":[]
               //注意这里的state值设置很关键,若为父节点,state="open"|"close",若为叶子节点,只能为空
               //否则出错,如图①
            }
        ]
        
    },
    {
        "id": 5,
        "text": "系统模块",
        "iconCls": "icon-feed",
        "checked": false,
        "attributes": {
            "url": null
        },
       "state": null 
    },
    {
        "id": 6,
        "text": "系统模块2",
        "iconCls": "icon-feed",
        "checked": false,
        "attributes": {
            "url": null
        }
        
    },
    {
        "id": 7,
        "text": "系统模块3",
        "iconCls": "icon-feed",
        "checked": false,
        "attributes": {
            "url": null
        }
        
    },
    {
        "id": 8,
        "text": "系统模块4",
        "iconCls": "icon-feed",
        "checked": false,
        "attributes": {
            "url": null
        }
        
    },
    {
        "id": 9,
        "text": "系统模块5",
        "iconCls": "icon-feed",
        "checked": false,
        "attributes": {
            "url": null
        }
        
    }
]

  

    如图①

正确的图是

二、tree加载方式

1、html格式

<ul id="tt" class="easyui-tree">   
    <li>   
        <span>Folder</span>   
        <ul>   
            <li>   
                <span>Sub Folder 1</span>   
                <ul>   
                    <li>   
                        <span><a href="#">File 11</a></span>   
                    </li>   
                    <li>   
                        <span>File 12</span>   
                    </li>   
                    <li>   
                        <span>File 13</span>   
                    </li>   
                </ul>   
            </li>   
            <li>   
                <span>File 2</span>   
            </li>   
            <li>   
                <span>File 3</span>   
            </li>   
        </ul>   
    </li>   
    <li>   
        <span>File21</span>   
    </li>   
</ul>  

  

2、加载json文件,如tree_data.json,内容如上
<ul id="tt"></ul>
$('#tt').tree({
url:'tree_data.json'
});

 

3、从后台数据库传json字符串值
①实体类
②tree json格式对应的实体类
③实体类Menu转化为TreeNode格式(tree json格式),进行递归调用返回树形菜单

 

import java.util.ArrayList;
import java.util.HashMap; import java.util.List; import java.util.Map; import sys.entity.Menu; public class TreeNodeUtil { public static List<TreeNode> tree(List<TreeNode>nodes,Integer id) { //递归转化为树形 List<TreeNode> treeNodes=new ArrayList<TreeNode>(); for(TreeNode treeNode : nodes) { TreeNode node=new TreeNode(); node.setId(treeNode.getId()); node.setText(treeNode.getText()); node.setAttributes(treeNode.getAttributes()); node.setIconCls(treeNode.getIconCls()); node.setState(treeNode.getState()); node.setPid(treeNode.getPid()); if(id==treeNode.getPid()){ node.setChildren(tree(nodes, node.getId())); treeNodes.add(node); } } return treeNodes; }
//转化为TreeNode节点 public static TreeNode toNode(Menu menu){ TreeNode node=new TreeNode(); node.setId(menu.getId()); node.setIconCls(menu.getIcon()); node.setPid(menu.getParentMenuId()); System.out.println(node.getPid()); node.setText(menu.getMenuName()); node.setState(menu.getState()); Map<String,Object>attributes=new HashMap<String,Object>(); attributes.put("url", menu.getUrl()); node.setAttributes(attributes); return node; } public static List<TreeNode>toListNode(List<Menu>menus){ List<TreeNode>nodes=new ArrayList<TreeNode>(); for(Menu menu:menus){ nodes.add(toNode(menu)); } return nodes; } }

  

④查询出需要的菜单记录,我这里是权限管理系统,一个角色对应多个菜单,通过角色id查询出菜单记录,一个用户有多个角色,所以多个角色对应的菜单可能有交集,这里采用rbac的白名单权限,获得最大的菜单权限。

@Override
	public List<Menu> getMenuByRoleId(Integer[] roleIds) {
		List<Menu>menus=new ArrayList<Menu>();
		for(Integer roleId:roleIds){
			List<Menu>menus1=menuMapper.selectByRoleId(roleId);
			for(Menu menu:menus1){
				if(!menus.contains(menu)){
					menus.add(menu); 
				}
			}
		}
		return menus;
}

  

⑤controller层代码
@ResponseBody
    @RequestMapping(value="treeView")
    public List<TreeNode> treeView(@RequestParam("roleIds")String roleIdStr){
        String param[]=roleIdStr.split(",");
        Integer[] roleIds=new Integer[param.length];
        for(int i=0;i<param.length;i++){
            roleIds[i]=Integer.parseInt(param[i]);
        }
        List<Menu>menus=menuService.getMenuByRoleId(roleIds);
        List<TreeNode>nodes=TreeNodeUtil.toListNode(menus);
        List<TreeNode>treeNodes=TreeNodeUtil.tree(nodes, 0);
        for(TreeNode node:nodes){
            System.out.println(node.getIconCls());
            System.out.println(node.getPid());
        }
        return treeNodes;
    }

  结果:

⑥数据库部分设计

posted @ 2017-04-11 12:25  hzhh123  阅读(5269)  评论(0编辑  收藏  举报