LeetCode 520. Detect Capital

problem:

 

Given a word, you need to judge whether the usage of capitals in it is right or not.

We define the usage of capitals in a word to be right when one of the following cases holds:

  1. All letters in this word are capitals, like "USA".
  2. All letters in this word are not capitals, like "leetcode".
  3. Only the first letter in this word is capital if it has more than one letter, like "Google".
Otherwise, we define that this word doesn't use capitals in a right way.

Example 1:

Input: "USA"
Output: True

Example 2:

Input: "FlaG"
Output: False

Note: The input will be a non-empty word consisting of uppercase and lowercase latin letters.

 

 

first:

复制代码
class Solution {
    public boolean detectCapitalUse(String word) {
        char[] charArray = word.toCharArray();
        if(Character.isLowerCase(charArray[0])){
            for(char c : charArray){
                if(Character.isUpperCase(c)){
                    return false;
                }
            }
            return true;
        }
        
        if(Character.isUpperCase(charArray[0])&&Character.isUpperCase(charArray[1])){
            for(char c : charArray){
                if(Character.isLowerCase(c)){
                    return false;
                }
            }
            return true;
        }
           
        if(Character.isUpperCase(charArray[0])&&Character.isLowerCase(charArray[1])){
            for(int i=2;i<charArray.length;i++){
                if(Character.isUpperCase(charArray[i])){
                    return false;
                }
            }
            return true;
        }  
           
        return false;   
    }
}
复制代码

 

result:

Submission Result: Runtime Error 
Runtime Error Message: Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1
    at Solution.detectCapitalUse(Solution.java:13)
    at __DriverSolution__.__helper__(__Driver__.java:4)
    at __Driver__.main(__Driver__.java:48)
Last executed input: "G"

 

second:

复制代码
class Solution {
    public boolean detectCapitalUse(String word) {
        char[] charArray = word.toCharArray();
        
        if(charArray.length==1){
            return true;
        }
        
        if(Character.isLowerCase(charArray[0])){
            for(char c : charArray){
                if(Character.isUpperCase(c)){
                    return false;
                }
            }
            return true;
        }
        
        if(Character.isUpperCase(charArray[0])&&Character.isUpperCase(charArray[1])){
            for(char c : charArray){
                if(Character.isLowerCase(c)){
                    return false;
                }
            }
            return true;
        }
           
        if(Character.isUpperCase(charArray[0])&&Character.isLowerCase(charArray[1])){
            for(int i=2;i<charArray.length;i++){
                if(Character.isUpperCase(charArray[i])){
                    return false;
                }
            }
            return true;
        }  
           
        return false;   
    }
}
复制代码

 

result:

discussion里得票最高的写法:

public class Solution {
    public boolean detectCapitalUse(String word) {
        int cnt = 0;
        for(char c: word.toCharArray()) if('Z' - c >= 0) cnt++;
        return ((cnt==0 || cnt==word.length()) || (cnt==1 && 'Z' - word.charAt(0)>=0));
    }
}

 

result:

 

third try:

复制代码
class Solution {
    public boolean detectCapitalUse(String word) {
        char[] charArray = word.toCharArray();
        
        if(charArray.length==1){
            return true;
        }
        
        if(!(0<='Z'-charArray[0])){
            for(char c : charArray){
                if(0<='Z'-c){
                    return false;
                }
            }
            return true;
        }
        
        if(0<='Z'-charArray[0]&&0<='Z'-charArray[1]){
            for(char c : charArray){
                if(!(0<='Z'-c)){
                    return false;
                }
            }
            return true;
        }
           
        if(0<='Z'-charArray[0]&&!(0<='Z'-charArray[1])){
            for(int i=2;i<charArray.length;i++){
                if(0<='Z'-charArray[i]){
                    return false;
                }
            }
            return true;
        }  
           
        return false;   
    }
}
复制代码

 

result:

 

Conclusion:

 可见Character.isUpperCase(char c)方法效率较低。其实现留待后续查看。

posted @   Zhao_Gang  阅读(154)  评论(0编辑  收藏  举报
编辑推荐:
· Linux系列:如何用 C#调用 C方法造成内存泄露
· AI与.NET技术实操系列(二):开始使用ML.NET
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
阅读排行:
· 阿里最新开源QwQ-32B,效果媲美deepseek-r1满血版,部署成本又又又降低了!
· 单线程的Redis速度为什么快?
· SQL Server 2025 AI相关能力初探
· 展开说说关于C#中ORM框架的用法!
· AI编程工具终极对决:字节Trae VS Cursor,谁才是开发者新宠?
点击右上角即可分享
微信分享提示