动态规划-LCS-Uncrossed Lines

2020-02-11 21:14:18

问题描述:

 

问题求解:

本质就是LCS。

    public int maxUncrossedLines(int[] A, int[] B) {
        int len1 = A.length;
        int len2 = B.length;
        int[][] dp = new int[len1 + 1][len2 + 1];
        for (int i = 1; i <= len1; i++) {
            for (int j = 1; j <= len2; j++) {
                if (A[i - 1] == B[j - 1]) {
                    dp[i][j] = dp[i - 1][j - 1] + 1;
                }
                else {
                    dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]);
                }
            }
        }
        return dp[len1][len2];
    }

  

 

posted @ 2020-02-11 21:23  hyserendipity  阅读(618)  评论(0编辑  收藏  举报