双向链表

class Node():
def __init__(self,item,pre=None,next=None):
self.item = item
self.next = next
self.pre = pre

class DoubleLinkList():
def __init__(self,node=None):
self.__head = node
def search(self,item):
cur = self.__head
while cur != None:
if cur.item == item:
return True
cur = cur.next
return False
def length(self):
cur = self.__head
count = 0
while cur != None:
count += 1
cur = cur.next
return count
def add(self,item):
node = Node(item)
if self.is_empty():
# 如果是空链表,将__head指向node
self.__head = node
else:
# 将node的next指向__head的头节点
node.next = self.__head
# 将__head的头节点的prev指向node
self.__head.pre = node
# 将__head 指向node
self.__head = node

def append(self, item):
node = Node(item)
if self.is_empty():
# 如果是空链表,将_head指向node
self.__head = node
else:
# 移动到链表尾部
cur = self.__head
while cur.next != None:
cur = cur.next
# 将尾节点cur的next指向node
cur.next = node
# 将node的prev指向cur
node.pre = cur
def travel(self):
cur = self.__head
while cur != None:
print (cur.item)
cur = cur.next
 
def is_empty(self):
return self.__head == None

def remove(self, item):
if self.is_empty():
return
else:
cur = self.__head
if cur.item == item:
# 如果首节点的元素即是要删除的元素
if cur.next == None:
# 如果链表只有这一个节点
self.__head = None
else:
# 将第二个节点的prev设置为None
cur.next.prev = None
# 将__head指向第二个节点
self.__head = cur.next
return
while cur != None:
if cur.item == item:
# 将cur的前一个节点的next指向cur的后一个节点
cur.pre.next = cur.next
# 将cur的后一个节点的prev指向cur的前一个节点
cur.next.pre = cur.pre
break
cur = cur.next

def insert(self, pos, item):
if pos <= 0:
self.add(item)
elif pos > (self.length()-1):
self.append(item)
else:
node = Node(item)
cur = self.__head
count = 0
# 移动到指定位置的前一个位置
while count < (pos-1):
count += 1
cur = cur.next
# 将node的prev指向cur
node.pre = cur
# 将node的next指向cur的下一个节点
node.next = cur.next
# 将cur的下一个节点的prev指向node
cur.next.pre = node
# 将cur的next指向node
cur.next = node


#导入单链表模块的类from singe_next import SingleLinkList#
if __name__ == "__main__":
ll = DoubleLinkList()
ll.add(1)
ll.add(0)
ll.append(0)
ll.insert(2, 4)
ll.insert(3, 4)
ll.insert(1, 5)
print ("length:", ll.length())
ll.travel()
print (ll.search(2))
print (ll.search(3))
ll.remove(1)
print ("length:", ll.length())
ll.travel()
posted @ 2018-01-23 11:29  hyolyn  阅读(103)  评论(0编辑  收藏  举报