Python实现屏幕截图

import time
import win32gui, win32ui, win32con, win32api


def window_capture(filename):
hwnd = 0 # 窗口的编号,0号表示当前活跃窗口
# 根据窗口句柄获取窗口的设备上下文DC(Divice Context)
hwndDC = win32gui.GetWindowDC(hwnd)
# 根据窗口的DC获取mfcDC
mfcDC = win32ui.CreateDCFromHandle(hwndDC)
# mfcDC创建可兼容的DC
saveDC = mfcDC.CreateCompatibleDC()
# 创建bigmap准备保存图片
saveBitMap = win32ui.CreateBitmap()
# 获取监控器信息
MoniterDev = win32api.EnumDisplayMonitors(None, None)
w = MoniterDev[0][2][2]
h = MoniterDev[0][2][3]
# print w,h   #图片大小
# 为bitmap开辟空间
saveBitMap.CreateCompatibleBitmap(mfcDC, w, h)
# 高度saveDC,将截图保存到saveBitmap中
saveDC.SelectObject(saveBitMap)
# 截取从左上角(0,0)长宽为(w,h)的图片
saveDC.BitBlt((0, 0), (w, h), mfcDC, (0, 0), win32con.SRCCOPY)
saveBitMap.SaveBitmapFile(saveDC, filename)


beg = time.time()
for i in range(10):
window_capture("haha.jpg")
end = time.time()
print(end - beg)
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输出结果为0.375秒,也就是说通过windows API每次截图只需要0.0375s,真是快得一逼呀。

使用PIL的ImageGrab模块
import time
from PIL import ImageGrab
import numpy as np
import cv2

beg = time.time()
debug = False
# img = ImageGrab.grab(bbox=(250, 161, 1141, 610))
img = ImageGrab.grab()
end = time.time()
print('time:',end - beg)

img.show()
img.save("screen.jpg")

# PIL image to OpenCV image
im = np.array(img)
cv2.imshow('cv image', im)
cv2.waitKey()

# OpenCV image to PIL image
im_pil = PIL.Image.fromarray(im)
im_pil.show(http://www.my516.com)

posted @ 2019-07-08 21:19  水至清明  阅读(1131)  评论(0编辑  收藏  举报