简单的字典排序,根据value值得大小排序:

def sort_dict(dict_words):
    """
    字典排序
    :param dict_words:
    :return:
    """
    keys = dict_words.keys()
    values = dict_words.values()

    list_one = [(key, val) for key, val in zip(keys, values)]
    list_sort = sorted(list_one, key=lambda x: x[1], reverse=True)

    return list_sort