[C#]判断是否是合法的IP4,IP6地址
判断一个字符串如果没有端口的话,利用IPAddress.TryParse很好判断,那么有端口怎么判断呢,正则表达式?还是其他方式?
关键代码:
/// <summary>
/// 判断是否是合法的IP4,IP6地址
/// </summary>
/// <param name="ip">需要判断的字符串</param>
/// <returns>合法则返回host部分,若不合法则返回空</returns>
public static string GetIPAddress(string ip)
{
string _ipAddress = string.Empty;
if (!string.IsNullOrEmpty(ip))
{
UriHostNameType _hostType = Uri.CheckHostName(ip);
if (_hostType == UriHostNameType.Unknown)//譬如 "192.168.1.1:8060"或者[2001:0DB8:02de::0e13]:9010
{
Uri _url;
if (Uri.TryCreate(string.Format("http://{0}", ip), UriKind.Absolute, out _url))
{
_ipAddress = IPAddressTryParse(_url.Host);
}
}
else if (_hostType == UriHostNameType.IPv4 || _hostType == UriHostNameType.IPv6)
{
_ipAddress = IPAddressTryParse(ip);
}
}
return _ipAddress;
}
private static string IPAddressTryParse(string ip)
{
string _ipAddress = string.Empty;
IPAddress _ipAdr;
if (IPAddress.TryParse(ip, out _ipAdr))
{
_ipAddress = _ipAdr.ToString();
}
return _ipAddress;
}
单元测试:
[TestMethod()]
public void GetIPAddressTest()
{
string _ip4Address1 = "192.168.1.1";
string _expected1 = "192.168.1.1";
string _actual1 = NetWorkToolV2.GetIPAddress(_ip4Address1);
Assert.AreEqual(_expected1, _actual1);
string _ip4Address2 = "192.168.1.1:8060";
string _expected2 = "192.168.1.1";
string _actual2 = NetWorkToolV2.GetIPAddress(_ip4Address2);
Assert.AreEqual(_expected2, _actual2);
string _ip6Address3 = "2001:0DB8:02de::0e13";
string _expected3 = "2001:DB8:2de::e13";
string _actual3 = NetWorkToolV2.GetIPAddress(_ip6Address3);
Assert.AreEqual(_expected3, _actual3,true);
string _ip6Address4 = "[2001:0DB8:2de::e13]:9010";
string _expected4 = "2001:DB8:2de::e13";
string _actual4 = NetWorkToolV2.GetIPAddress(_ip6Address4);
Assert.AreEqual(_expected4, _actual4, true);
string _ipAddress5 = "erroriptest";
string _expected5 = string.Empty;
string _actual5 = NetWorkToolV2.GetIPAddress(_ipAddress5);
Assert.AreEqual(_expected5, _actual5);
}
测试结果:
希望有所帮助!