C++ 模板类类型限定

#include <iostream>
#include <type_traits>
using namespace std;
namespace
{
    class IAnimal
    {
    public:
        virtual void say() = 0;
    };

    class Dog : IAnimal
    {
    public:
        void say() override
        {
            cout << "我是 狗!!" << '\n';
        }
    };

    class Cat : IAnimal
    {
    public:
        void say() override
        {
            cout << "我是 猫!!" << '\n';
        }
    };

    class Horse
    {
    public:
        void say()
        {
            cout << "我是 马!!" << '\n';
        }
    };
}

template <typename T,
    typename = typename std::enable_if<std::is_base_of<IAnimal, T>::value>::type>
    class MyPet
{
public:
    void sayWhat()
    {
        m_pet.say();
    }
private:
    T m_pet;
};

int main()
{
    MyPet<Dog> myDog;
    myDog.sayWhat();

    MyPet<Cat> myCat;
    myCat.sayWhat();
    
    // 放开注释 typename = typename std::enable_if ... ::type> type 会找不到而报错
   /* MyPet<Horse> myHorse;
    myHorse.sayWhat();*/

    system("pause");
    return EXIT_SUCCESS;
}

输出：

我是 狗!!
我是 猫!!

template <typename T,
    typename = typename std::enable_if<std::is_base_of<IAnimal, T>::value>::type>
    class MyPet
{
}

is_base_of 为 true 会展开成：

template <typename T,
    typename = void
    class MyPet
{
}

is_base_of 为 false 时会找不到 Type 而报错。

---

参考：https://blog.csdn.net/m0_60259364/article/details/129965365