[leetcode]Rotate Image
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Follow up:
Could you do this in-place?
CC上的原题,大概还记得,时间复杂度O(n ^ 2),空间O(1)。
算法思路:
每一次转置相映成环的四个点。这四个点的坐标与n有关,可通过归纳法求出四个对应点的坐标关系
代码如下:
1 public class Solution { 2 public void rotate(int[][] matrix) { 3 if(matrix == null || matrix.length == 0 ) return ; 4 int n = matrix.length; 5 int tem = 0; 6 for(int i = 0; i < n >> 1; i++){ 7 for(int j = i; j < n - i - 1; j++){ 8 tem = matrix[i][j]; 9 matrix[i][j] = matrix[n - 1 - j][i]; 10 matrix[n - 1 - j][i] = matrix[n - 1 - i][n - 1- j]; 11 matrix[n - 1 - i][n - 1 - j] = matrix[j][n - 1 - i]; 12 matrix[j][n - 1 - i] = tem; 13 } 14 } 15 } 16 }
这四个坐标的对应关系真心蛋疼.....