[leetcode]Length of Last Word

Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5

算法思路:

这道题貌似是leetcode中最easy的一道了吧,心情不好,状态不佳,就找软柿子捏吧(注意字符串以空格结尾)

代码如下:

 1 public class Solution {
 2     public int lengthOfLastWord(String s) {
 3         int length = 0;
 4         for(int i = s.length() - 1; i >= 0; i--){
 5             if(s.charAt(i) != ' '){
 6                 while(i >= 0 && s.charAt(i) != ' '){
 7                     length++;
 8                     i--;
 9                 }
10                 return length;
11             }
12         }
13         return 0;
14     }
15 }

posted on 2014-07-24 22:24  喵星人与汪星人  阅读(131)  评论(0编辑  收藏  举报