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1114 Family Property

This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average area and number of sets of their real estate.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (1000). Then N lines follow, each gives the infomation of a person who owns estate in the format:

ID Father Mother Child1​​Childk​​ Mestate​​ Area

where ID is a unique 4-digit identification number for each person; Father and Mother are the ID's of this person's parents (if a parent has passed away, -1 will be given instead); k (0k5) is the number of children of this person; Childi​​'s are the ID's of his/her children; Mestate​​ is the total number of sets of the real estate under his/her name; and Area is the total area of his/her estate.

Output Specification:

For each case, first print in a line the number of families (all the people that are related directly or indirectly are considered in the same family). Then output the family info in the format:

ID M AVGsets​​ AVGarea​​

where ID is the smallest ID in the family; M is the total number of family members; AVGsets​​ is the average number of sets of their real estate; and AVGarea​​ is the average area. The average numbers must be accurate up to 3 decimal places. The families must be given in descending order of their average areas, and in ascending order of the ID's if there is a tie.

知识点:并查集

注意并查集的写法

 1 #include <iostream>
 2 #include <algorithm>
 3 #include <vector>
 4 using namespace std;
 5 const int maxn = 10003;
 6 
 7 int ManSet[maxn];
 8 int Property[maxn][2];
 9 int used[maxn];
10 //set<int>
11 
12 bool cmp(int a,int b){
13     if(Property[a][1]/(-ManSet[a]+0.0)==Property[b][1]/(-ManSet[b]+0.0)){
14         return a<b;
15     }
16     return Property[a][1]/(-ManSet[a]+0.0)>Property[b][1]/(-ManSet[b]+0.0);
17 }
18 
19 int Find(int v){
20     if(ManSet[v]<=-1){
21         return v;
22     }
23     return ManSet[v] = Find(ManSet[v]);
24 }
25 
26 int Unite(int n1, int n2){
27     
28     if(n1<n2){
29         ManSet[n1] += ManSet[n2];
30         ManSet[n2] = n1;
31         return n1;
32     }else{
33         ManSet[n2] += ManSet[n1];
34         ManSet[n1] = n2;
35         return n2;
36     }
37 }
38 
39 int main(int argc, char *argv[]) {
40     int n;
41     fill(ManSet,ManSet+maxn,-1);
42     fill(Property[0],Property[0]+maxn*2,0);
43     fill(used,used+maxn,0);
44     
45     scanf("%d",&n);
46     int man,fa,mo,k,tmpc,m,area;
47     for(int i=0;i<n;i++){
48         //printf("\n");
49         scanf("%d %d %d",&man,&fa,&mo);
50         used[man] = used[fa] = used[mo] = 1;
51         //printf("\n. %d %d,%d\n",Find(man),i,n);
52         man = Find(man); //printf("%d  ",man);
53         if(fa!=-1){
54             fa = Find(fa);
55             if(fa!=man){
56                 man = Unite(man,fa); //printf("%d ",man);
57             }
58         }
59         man = Find(man);
60         if(mo!=-1){
61             mo = Find(mo);
62             if(mo!=man){
63                 man = Unite(man,mo);//printf("%d ",man);
64             }
65         }
66         scanf("%d",&k);
67         for(int j=0;j<k;j++){
68             scanf("%d",&tmpc);
69             used[tmpc] = 1;
70             tmpc = Find(tmpc);
71             man = Find(man);
72             if(man!=tmpc){
73                 man = Unite(man,tmpc);//printf("%d ",man);
74             }
75         }
76         scanf("%d %d",&m,&area);
77         Property[man][0] += m;
78         Property[man][1] += area;
79     }
80     for(int i=0;i<maxn;i++){
81         if(used[i]==1&&ManSet[i]>0&&Property[i][0]>0){
82             int an = Find(i);
83             Property[an][0]+=Property[i][0];
84             Property[an][1]+=Property[i][1];
85         }
86     }
87     vector<int> list;
88     for(int i=0;i<maxn;i++){
89         if(used[i]==1&&ManSet[i]<0){
90             list.push_back(i);
91             //printf("%04d %d %.3f %.3f\n",i,(-ManSet[i]),Property[i][0]/(-ManSet[i]+0.0),Property[i][1]/(-ManSet[i]+0.0));
92         }
93     }
94     sort(list.begin(), list.end(), cmp);
95     printf("%d\n",list.size());
96     for(int i=0;i<list.size();i++){
97         printf("%04d %d %.3f %.3f\n",list[i],(-ManSet[list[i]]),Property[list[i]][0]/(-ManSet[list[i]]+0.0),Property[list[i]][1]/(-ManSet[list[i]]+0.0));
98     }
99 }

 

posted on 2018-11-07 20:11  iojafekniewg  阅读(334)  评论(0编辑  收藏  举报

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