摘要:
暴力枚举下,可以发现规律View Code #include<stdio.h>long long a[1000009];int main(){ a[1]=1; int n,i,id=1; while(scanf("%d",&n)!=EOF) { id=1; for(i=2;i<=n;i+=2) { a[i]=a[i+1]=(a[i-1]+a[id])%1000000000; id++; } printf("%lld\n",a[n]); } return 0;} 阅读全文
posted @ 2011-07-28 18:19 huhuuu 阅读(286) 评论(0) 推荐(0) 编辑