1019 General Palindromic Number

代码如下：

#include<iostream>

using namespace std;
int jishu = 0;
int stem[50000] = {0};
void trans(int n,int base){
    while(n != 0){
        stem[jishu++] = n%base;
        n /= base;
    }
}
int main(){
    int n,base;
    cin >> n >> base;
    trans(n,base);
    //cout << jishu ;
    bool flag = false;
    for(int i = 0; i < jishu/2; i++){
        if(stem[i] != stem[jishu-i-1]){
            flag = !flag;
            break;
        }
    }
    if(flag) cout << "No" << endl;
    else cout << "Yes" << endl;
    for(int i = jishu-1; i > 0; i--){
        cout << stem[i] << " ";
    }
    cout << stem[0];
    return 0;
}