【Swagger2】【1】匹配多个controller

前言：项目中有多个模块，所以有多个controller层。我是用方案二的

正文：

方案一：使用多个controller的共同拥有的父类

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.xx"))
            .paths(PathSelectors.any())
            .build();
}

方法二：指定所有controller的都实现的一个接口，比如@RestController

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.withClassAnnotation(RestController.class))
            .paths(PathSelectors.any())
            .build();
}

错误的两种写法

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.xx.*.controller"))
            .paths(PathSelectors.any())
            .build();
}

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.xx.course.controller"))
            .apis(RequestHandlerSelectors.basePackage("com.xx.user.controller"))
            .paths(PathSelectors.any())
            .build();
}

参考博客：

swagger2 如何匹配多个controller - 贾树丙 - 博客园
http://www.cnblogs.com/acm-bingzi/p/swagger2-controller.html