LaunchedURLClassLoade
public class Handler extends URLStreamHandler {
private static final String SEPARATOR = "!/";
private static SoftReference<Map<File, JarFile>> rootFileCache;
@Override
protected URLConnection openConnection(URL url) throws IOException {
if (this.jarFile != null) {
return new JarURLConnection(url, this.jarFile);
}
try {
return new JarURLConnection(url, getRootJarFileFromUrl(url));
}
catch (Exception ex) {
return openFallbackConnection(url, ex);
}
}
public JarFile getRootJarFileFromUrl(URL url) throws IOException {
String spec = url.getFile();
int separatorIndex = spec.indexOf(SEPARATOR);
if (separatorIndex == -1) {
throw new MalformedURLException("Jar URL does not contain !/ separator");
}
String name = spec.substring(0, separatorIndex);
return getRootJarFile(name);
}
ClassLoader如何读取到Resource
对于一个ClassLoader,它需要哪些能力?
- 查找资源
- 读取资源
对应的API是:
public URL findResource(String name)
public InputStream getResourceAsStream(String name)
- 1
- 2
上面提到,Spring boot构造LaunchedURLClassLoader时,传递了一个URL[]数组。数组里是lib目录下面的jar的URL。
对于一个URL,JDK或者ClassLoader如何知道怎么读取到里面的内容的?
实际上流程是这样子的:
- LaunchedURLClassLoader.loadClass
- URL.getContent()
- URL.openConnection()
- Handler.openConnection(URL)
最终调用的是JarURLConnection的getInputStream()函数。
//org.springframework.boot.loader.jar.JarURLConnection
@Override
public InputStream getInputStream() throws IOException {
connect();
if (this.jarEntryName.isEmpty()) {
throw new IOException("no entry name specified");
}
return this.jarEntryData.getInputStream();
}
- 1
从一个URL,到最终读取到URL里的内容,整个过程是比较复杂的,总结下:
- spring boot注册了一个Handler来处理”jar:”这种协议的URL
- spring boot扩展了JarFile和JarURLConnection,内部处理jar in jar的情况
- 在处理多重jar in jar的URL时,spring boot会循环处理,并缓存已经加载到的JarFile
- 对于多重jar in jar,实际上是解压到了临时目录来处理,可以参考JarFileArchive里的代码
- 在获取URL的InputStream时,最终获取到的是JarFile里的JarEntryData
这里面的细节很多,只列出比较重要的一些点。
然后,URLClassLoader是如何getResource的呢?
URLClassLoader在构造时,有URL[]数组参数,它内部会用这个数组来构造一个URLClassPath:
URLClassPath ucp = new URLClassPath(urls);
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在 URLClassPath 内部会为这些URLS 都构造一个Loader,然后在getResource时,会从这些Loader里一个个去尝试获取。
如果获取成功的话,就像下面那样包装为一个Resource。
Resource getResource(final String name, boolean check) {
final URL url;
try {
url = new URL(base, ParseUtil.encodePath(name, false));
} catch (MalformedURLException e) {
throw new IllegalArgumentException("name");
}
final URLConnection uc;
try {
if (check) {
URLClassPath.check(url);
}
uc = url.openConnection();
InputStream in = uc.getInputStream();
if (uc instanceof JarURLConnection) {
/* Need to remember the jar file so it can be closed
* in a hurry.
*/
JarURLConnection juc = (JarURLConnection)uc;
jarfile = JarLoader.checkJar(juc.getJarFile());
}
} catch (Exception e) {
return null;
}
return new Resource() {
public String getName() { return name; }
public URL getURL() { return url; }
public URL getCodeSourceURL() { return base; }
public InputStream getInputStream() throws IOException {
return uc.getInputStream();
}
public int getContentLength() throws IOException {
return uc.getContentLength();
}
};
}