mysql的子查询详解

分类：
按子查询出现的位置：
    select后面：
        仅仅支持标量子查询

    from后面：
        支持表子查询
    where或having后面：★
        标量子查询（单行） √
        列子查询（多行） √

        行子查询

    exists后面（相关子查询）
        表子查询
按结果集的行列数不同：
    标量子查询（结果集只有一行一列）
    列子查询（结果集只有一列多行）
    行子查询（结果集有一行多列）
    表子查询（结果集一般为多行多列）

#一、where或having后面
/*
1、标量子查询（单行子查询）
2、列子查询（多行子查询）

3、行子查询（多列多行）

特点：
①子查询放在小括号内
②子查询一般放在条件的右侧
③标量子查询，一般搭配着单行操作符使用
> < >= <= = <>

列子查询，一般搭配着多行操作符使用
in、any/some、all <>all =not in any=in any(等于其中的一个) all(所有满足)

④子查询的执行优先于主查询执行，主查询的条件用到了子查询的结果

#1.标量子查询★

#案例1：谁的工资比 Abel 高?

#①查询Abel的工资

SELECT salary
FROM employees
WHERE last_name = 'Abel'

#②查询员工的信息，满足 salary>①结果

SELECT *
FROM employees
WHERE salary>(
 
    SELECT salary
    FROM employees
    WHERE last_name = 'Abel'
 
);

#案例2：返回job_id与141号员工相同，salary比143号员工多的员工姓名，job_id 和工资

#①查询141号员工的job_id

SELECT job_id
FROM employees
WHERE employee_id = 141

#②查询143号员工的salary

SELECT salary
FROM employees
WHERE employee_id = 143

#③查询员工的姓名，job_id 和工资，要求job_id=①并且salary>②

SELECT last_name,job_id,salary
FROM employees
WHERE job_id = (
    SELECT job_id
    FROM employees
    WHERE employee_id = 141
) AND salary>(
    SELECT salary
    FROM employees
    WHERE employee_id = 143
 
);

#案例3：返回公司工资最少的员工的last_name,job_id和salary

#①查询公司的最低工资

SELECT MIN(salary)
FROM employees

#②查询last_name,job_id和salary，要求salary=①

SELECT last_name,job_id,salary
FROM employees
WHERE salary=(
    SELECT MIN(salary)
    FROM employees
);

#案例4：查询最低工资大于50号部门最低工资的部门id和其最低工资

#①查询50号部门的最低工资

SELECT  MIN(salary)
FROM employees
WHERE department_id = 50

#②查询每个部门的最低工资

SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id

#③ 在②基础上筛选，满足min(salary)>①

SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id
HAVING MIN(salary)>(
    SELECT  MIN(salary)
    FROM employees
    WHERE department_id = 50
);

#2.列子查询（多行子查询）★

#案例1：返回location_id是1400或1700的部门中的所有员工姓名

#①查询location_id是1400或1700的部门编号

SELECT DISTINCT department_id
FROM departments
WHERE location_id IN(1400,1700)

#②查询员工姓名，要求部门号是①列表中的某一个

SELECT last_name
FROM employees
WHERE department_id  <>ALL(
    SELECT DISTINCT department_id
    FROM departments
    WHERE location_id IN(1400,1700)
);

#案例2：返回其它工种中比job_id为‘IT_PROG’工种任一工资低的员工的员工号、姓名、job_id 以及salary

#①查询job_id为‘IT_PROG’部门任一工资

SELECT DISTINCT salary
FROM employees
WHERE job_id = 'IT_PROG'

#②查询员工号、姓名、job_id 以及salary，salary<(①)的任意一个

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<ANY(
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'
 
) AND job_id<>'IT_PROG';

#或

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<(
    SELECT MAX(salary)
    FROM employees
    WHERE job_id = 'IT_PROG'
 
) AND job_id<>'IT_PROG';

#案例3：返回其它部门中比job_id为‘IT_PROG’部门所有工资都低的员工的员工号、姓名、job_id 以及salary

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<ALL(
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'
 
) AND job_id<>'IT_PROG';

#或

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<(
    SELECT MIN( salary)
    FROM employees
    WHERE job_id = 'IT_PROG'
 
) AND job_id<>'IT_PROG';

#3、行子查询（结果集一行多列或多行多列）

#案例：查询员工编号最小并且工资最高的员工信息

SELECT * 
FROM employees
WHERE (employee_id,salary)=(
    SELECT MIN(employee_id),MAX(salary)
    FROM employees
);

#①查询最小的员工编号

SELECT MIN(employee_id)
FROM employees

#②查询最高工资

SELECT MAX(salary)
FROM employees

#③查询员工信息

SELECT *
FROM employees
WHERE employee_id=(
    SELECT MIN(employee_id)
    FROM employees
 
 
)AND salary=(
    SELECT MAX(salary)
    FROM employees
 
);

#二、select后面
/*
仅仅支持标量子查询
*/
#案例：查询每个部门的员工个数

SELECT d.*,(
 
    SELECT COUNT(*)
    FROM employees e
    WHERE e.department_id = d.`department_id`
 ) 个数
 FROM departments d;

#案例2：查询员工号=102的部门名

SELECT (
    SELECT department_name,e.department_id
    FROM departments d
    INNER JOIN employees e
    ON d.department_id=e.department_id
    WHERE e.employee_id=102
    
) 部门名;

#三、from后面
/*
将子查询结果充当一张表，要求必须起别名
*/

#案例：查询每个部门的平均工资的工资等级
#①查询每个部门的平均工资

SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id

SELECT * FROM job_grades;

#②连接①的结果集和job_grades表，筛选条件平均工资 between lowest_sal and highest_sal

SELECT  ag_dep.*,g.`grade_level`
FROM (
    SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id
) ag_dep
INNER JOIN job_grades g
ON ag_dep.ag BETWEEN lowest_sal AND highest_sal;

#四、exists后面（相关子查询）

/*
语法：
exists(完整的查询语句) 外查询先执行
结果：
1或0

SELECT EXISTS(SELECT employee_id FROM employees WHERE salary=300000);

#案例1：查询有员工的部门名#in

SELECT department_name
FROM departments d
WHERE d.`department_id` IN(
    SELECT department_id
    FROM employees
 
)

#exists

SELECT department_name
FROM departments d
WHERE EXISTS(
    SELECT *
    FROM employees e
    WHERE d.`department_id`=e.`department_id`
);

#案例2：查询没有女朋友的男神信息

#in

SELECT bo.*
FROM boys bo
WHERE bo.id NOT IN(
    SELECT boyfriend_id
    FROM beauty
)

#exists

SELECT bo.*
FROM boys bo
WHERE NOT EXISTS(
    SELECT boyfriend_id
    FROM beauty b
    WHERE bo.`id`=b.`boyfriend_id`
);

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End

posted @ 2022-01-25 18:05 树下水月阅读(788) 评论(0) 编辑收藏举报

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